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人気のある三角関数 >

2sin^2(x)-9sin(x)-5=0

解

2 sin^{2} (x) - 9 sin (x) - 5 = 0

解

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

+1

度

x = 21 0^{\circ} + 36 0^{\circ} n, x = 33 0^{\circ} + 36 0^{\circ} n

解答ステップ

2 sin^{2} (x) - 9 sin (x) - 5 = 0

置換で解く

2 sin^{2} (x) - 9 sin (x) - 5 = 0

仮定:

sin (x) = u

2 u^{2} - 9 u - 5 = 0

2 u^{2} - 9 u - 5 = 0 : u = 5, u = - \frac{1}{2}

2 u^{2} - 9 u - 5 = 0

解くとthe二次式

2 u^{2} - 9 u - 5 = 0

二次Equationの公式:

次の場合:

a = 2, b = - 9, c = - 5

u_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

u_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 (- 5) = 11

(- 9)^{2} - 4 \cdot 2 (- 5)

規則を適用

- (- a) = a

= (- 9)^{2} + 4 \cdot 2 \cdot 5

指数の規則を適用する:

n

が偶数であれば

(- a)^{n} = a^{n}

(- 9)^{2} = 9^{2}

= 9^{2} + 4 \cdot 2 \cdot 5

数を乗じる:

4 \cdot 2 \cdot 5 = 40

= 9^{2} + 40

9^{2} = 81

= 81 + 40

数を足す:

81 + 40 = 121

= 121

数を因数に分解する:

121 = 1 1^{2}

= 1 1^{2}

累乗根の規則を適用する:

n a^{n} = a

1 1^{2} = 11

= 11

u_{1, 2} = \frac{- ( - 9 ) \pm 11}{2 \cdot 2}

解を分離する

u_{1} = \frac{- ( - 9 ) + 11}{2 \cdot 2}, u_{2} = \frac{- ( - 9 ) - 11}{2 \cdot 2}

u = \frac{- ( - 9 ) + 11}{2 \cdot 2} : 5

\frac{- ( - 9 ) + 11}{2 \cdot 2}

規則を適用

- (- a) = a

= \frac{9 + 11}{2 \cdot 2}

数を足す:

9 + 11 = 20

= \frac{20}{2 \cdot 2}

数を乗じる:

2 \cdot 2 = 4

= \frac{20}{4}

数を割る:

\frac{20}{4} = 5

= 5

u = \frac{- ( - 9 ) - 11}{2 \cdot 2} : - \frac{1}{2}

\frac{- ( - 9 ) - 11}{2 \cdot 2}

規則を適用

- (- a) = a

= \frac{9 - 11}{2 \cdot 2}

数を引く:

9 - 11 = - 2

= \frac{- 2}{2 \cdot 2}

数を乗じる:

2 \cdot 2 = 4

= \frac{- 2}{4}

分数の規則を適用する:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{2}{4}

共通因数を約分する:

2

= - \frac{1}{2}

二次equationの解:

u = 5, u = - \frac{1}{2}

代用を戻す

u = sin (x)

sin (x) = 5, sin (x) = - \frac{1}{2}

sin (x) = 5, sin (x) = - \frac{1}{2}

sin (x) = 5 :

解なし

sin (x) = 5

- 1 \leq sin (x) \leq 1

解なし

sin (x) = - \frac{1}{2} : x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

sin (x) = - \frac{1}{2}

以下の一般解

sin (x) = - \frac{1}{2}

sin (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

すべての解を組み合わせる

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

グラフ

人気の例

2sin^2(x)=5cos(x)-1

2 sin^{2} (x) = 5 cos (x) - 1

solvefor x,sec(x+10)=5.759

so l v e f or x, sec (x + 1 0^{\circ}) = 5.759

tan(x)cot(x)+2cot(x)=0

tan (x) cot (x) + 2 cot (x) = 0

3cos(x)=sqrt(3)sin(x)

3 cos (x) = 3 sin (x)

cos(θ)=-(2sqrt(5))/5

cos (θ) = - \frac{2 5}{5}