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5cos^2(x)=4-3sin^2(x)

Solución

5 cos^{2} (x) = 4 - 3 sin^{2} (x)

Solución

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Grados

x = 4 5^{\circ} + 36 0^{\circ} n, x = 13 5^{\circ} + 36 0^{\circ} n, x = 22 5^{\circ} + 36 0^{\circ} n, x = 31 5^{\circ} + 36 0^{\circ} n

Pasos de solución

5 cos^{2} (x) = 4 - 3 sin^{2} (x)

Restar

4 - 3 sin^{2} (x)

de ambos lados

5 cos^{2} (x) - 4 + 3 sin^{2} (x) = 0

Re-escribir usando identidades trigonométricas

- 4 + 3 sin^{2} (x) + 5 cos^{2} (x)

Utilizar la identidad pitagórica:

cos^{2} (x) + sin^{2} (x) = 1

cos^{2} (x) = 1 - sin^{2} (x)

= - 4 + 3 sin^{2} (x) + 5 (1 - sin^{2} (x))

Simplificar

- 4 + 3 sin^{2} (x) + 5 (1 - sin^{2} (x)) : - 2 sin^{2} (x) + 1

- 4 + 3 sin^{2} (x) + 5 (1 - sin^{2} (x))

Expandir

5 (1 - sin^{2} (x)) : 5 - 5 sin^{2} (x)

5 (1 - sin^{2} (x))

Poner los parentesis utilizando:

a (b - c) = ab - a c

a = 5, b = 1, c = sin^{2} (x)

= 5 \cdot 1 - 5 sin^{2} (x)

Multiplicar los numeros:

5 \cdot 1 = 5

= 5 - 5 sin^{2} (x)

= - 4 + 3 sin^{2} (x) + 5 - 5 sin^{2} (x)

Simplificar

- 4 + 3 sin^{2} (x) + 5 - 5 sin^{2} (x) : - 2 sin^{2} (x) + 1

- 4 + 3 sin^{2} (x) + 5 - 5 sin^{2} (x)

Agrupar términos semejantes

= 3 sin^{2} (x) - 5 sin^{2} (x) - 4 + 5

Sumar elementos similares:

3 sin^{2} (x) - 5 sin^{2} (x) = - 2 sin^{2} (x)

= - 2 sin^{2} (x) - 4 + 5

Sumar/restar lo siguiente:

- 4 + 5 = 1

= - 2 sin^{2} (x) + 1

= - 2 sin^{2} (x) + 1

= - 2 sin^{2} (x) + 1

1 - 2 sin^{2} (x) = 0

Usando el método de sustitución

1 - 2 sin^{2} (x) = 0

Sea:

sin (x) = u

1 - 2 u^{2} = 0

1 - 2 u^{2} = 0 : u = \frac{1}{2}, u = - \frac{1}{2}

1 - 2 u^{2} = 0

Mover

1

al lado derecho

1 - 2 u^{2} = 0

Restar

1

de ambos lados

1 - 2 u^{2} - 1 = 0 - 1

Simplificar

- 2 u^{2} = - 1

- 2 u^{2} = - 1

Dividir ambos lados entre

- 2

- 2 u^{2} = - 1

Dividir ambos lados entre

- 2

\frac{- 2 u ^{2}}{- 2} = \frac{- 1}{- 2}

Simplificar

u^{2} = \frac{1}{2}

u^{2} = \frac{1}{2}

Para

x^{2} = f (a)

las soluciones son

x = f (a), - f (a)

u = \frac{1}{2}, u = - \frac{1}{2}

Sustituir en la ecuación

u = sin (x)

sin (x) = \frac{1}{2}, sin (x) = - \frac{1}{2}

sin (x) = \frac{1}{2}, sin (x) = - \frac{1}{2}

sin (x) = \frac{1}{2} : x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

sin (x) = \frac{1}{2}

Soluciones generales para

sin (x) = \frac{1}{2}

tabla de valores periódicos con

2 πn

intervalos:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

sin (x) = - \frac{1}{2} : x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

sin (x) = - \frac{1}{2}

Soluciones generales para

sin (x) = - \frac{1}{2}

tabla de valores periódicos con

2 πn

intervalos:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Combinar toda las soluciones

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Ejemplos populares

(18cos(2θ)+2+cos(θ))/2 =0

\frac{18 cos ( 2 θ ) + 2 + cos ( θ )}{2} = 0

0=3sin(x-1/2 pi)+2

0 = 3 sin (x - \frac{1}{2} π) + 2

2sin^2(x)=3sin(x)

2 sin^{2} (x) = 3 sin (x)

5+2sin(x)-7=0

5 + 2 sin (x) - 7 = 0

0=4sin(4x+3pi)

0 = 4 sin (4 x + 3 π)