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tan^2(θ)=sec^2(θ)+1

Solución

tan^{2} (θ) = sec^{2} (θ) + 1

Solución

Sin soluci \overset{o}{ˊ} n para θ \in R

Pasos de solución

tan^{2} (θ) = sec^{2} (θ) + 1

Restar

sec^{2} (θ) + 1

de ambos lados

tan^{2} (θ) - sec^{2} (θ) - 1 = 0

Expresar con seno, coseno

- 1 - sec^{2} (θ) + tan^{2} (θ)

Utilizar la identidad trigonométrica básica:

sec (x) = \frac{1}{cos ( x )}

= - 1 - (\frac{1}{cos ( θ )})^{2} + tan^{2} (θ)

Utilizar la identidad trigonométrica básica:

tan (x) = \frac{sin ( x )}{cos ( x )}

= - 1 - (\frac{1}{cos ( θ )})^{2} + (\frac{sin ( θ )}{cos ( θ )})^{2}

Simplificar

- 1 - (\frac{1}{cos ( θ )})^{2} + (\frac{sin ( θ )}{cos ( θ )})^{2} : \frac{- cos ^{2} ( θ ) - 1 + sin ^{2} ( θ )}{cos ^{2} ( θ )}

- 1 - (\frac{1}{cos ( θ )})^{2} + (\frac{sin ( θ )}{cos ( θ )})^{2}

(\frac{1}{cos ( θ )})^{2} = \frac{1}{cos ^{2} ( θ )}

(\frac{1}{cos ( θ )})^{2}

Aplicar las leyes de los exponentes:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{cos ^{2} ( θ )}

Aplicar la regla

1^{a} = 1

1^{2} = 1

= \frac{1}{cos ^{2} ( θ )}

(\frac{sin ( θ )}{cos ( θ )})^{2} = \frac{sin ^{2} ( θ )}{cos ^{2} ( θ )}

(\frac{sin ( θ )}{cos ( θ )})^{2}

Aplicar las leyes de los exponentes:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{sin ^{2} ( θ )}{cos ^{2} ( θ )}

= - 1 - \frac{1}{cos ^{2} ( θ )} + \frac{sin ^{2} ( θ )}{cos ^{2} ( θ )}

Combinar las fracciones usando el mínimo común denominador:

\frac{- 1 + sin ^{2} ( θ )}{cos ^{2} ( θ )}

Aplicar la regla

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 + sin ^{2} ( θ )}{cos ^{2} ( θ )}

= - 1 + \frac{sin ^{2} ( θ ) - 1}{cos ^{2} ( θ )}

Convertir a fracción:

1 = \frac{1 cos ^{2} ( θ )}{cos ^{2} ( θ )}

= - \frac{1 \cdot cos ^{2} ( θ )}{cos ^{2} ( θ )} + \frac{- 1 + sin ^{2} ( θ )}{cos ^{2} ( θ )}

Ya que los denominadores son iguales, combinar las fracciones:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot cos ^{2} ( θ ) - 1 + sin ^{2} ( θ )}{cos ^{2} ( θ )}

Multiplicar:

1 \cdot cos^{2} (θ) = cos^{2} (θ)

= \frac{- cos ^{2} ( θ ) - 1 + sin ^{2} ( θ )}{cos ^{2} ( θ )}

= \frac{- cos ^{2} ( θ ) - 1 + sin ^{2} ( θ )}{cos ^{2} ( θ )}

\frac{- 1 - cos ^{2} ( θ ) + sin ^{2} ( θ )}{cos ^{2} ( θ )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- 1 - cos^{2} (θ) + sin^{2} (θ) = 0

Re-escribir usando identidades trigonométricas

- 1 - cos^{2} (θ) + sin^{2} (θ)

Utilizar la identidad trigonométrica del ángulo doble:

cos^{2} (x) - sin^{2} (x) = cos (2 x)

- cos^{2} (x) + sin^{2} (x) = - cos (2 x)

= - 1 - cos (2 θ)

- 1 - cos (2 θ) = 0

Mover

1

al lado derecho

- 1 - cos (2 θ) = 0

Sumar

1

a ambos lados

- 1 - cos (2 θ) + 1 = 0 + 1

Simplificar

- cos (2 θ) = 1

- cos (2 θ) = 1

Dividir ambos lados entre

- 1

- cos (2 θ) = 1

Dividir ambos lados entre

- 1

\frac{- cos ( 2 θ )}{- 1} = \frac{1}{- 1}

Simplificar

cos (2 θ) = - 1

cos (2 θ) = - 1

Soluciones generales para

cos (2 θ) = - 1

cos (x)

tabla de valores periódicos con

2 πn

intervalos:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

2 θ = π + 2 πn

2 θ = π + 2 πn

Resolver

2 θ = π + 2 πn : θ = \frac{π}{2} + πn

2 θ = π + 2 πn

Dividir ambos lados entre

2

2 θ = π + 2 πn

Dividir ambos lados entre

2

\frac{2 θ}{2} = \frac{π}{2} + \frac{2 πn}{2}

Simplificar

θ = \frac{π}{2} + πn

θ = \frac{π}{2} + πn

θ = \frac{π}{2} + πn

Siendo que la ecuación esta indefinida para:

\frac{π}{2} + πn

Sin soluci \overset{o}{ˊ} n para θ \in R

Ejemplos populares

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cos (2 B) = \frac{21}{35}, cos (B)

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cos^2(x)+sin^2(x)-2sin(x)=0,0<= x<= 2pi

cos^{2} (x) + sin^{2} (x) - 2 sin (x) = 0, 0 \leq x \leq 2 π