해법
12⋅9.8⋅sin(a)−0.6⋅12⋅9.8⋅cos(a)=12⋅1.79
해법
a=−2.75844…+2πn,a=0.69769…+2πn
+1
도
a=−158.04722…∘+360∘n,a=39.97473…∘+360∘n솔루션 단계
12⋅9.8sin(a)−0.6⋅12⋅9.8cos(a)=12⋅1.79
더하다 0.6129.8cos(a) 양쪽으로117.6sin(a)=21.48+70.56cos(a)
양쪽을 제곱(117.6sin(a))2=(21.48+70.56cos(a))2
빼다 (21.48+70.56cos(a))2 양쪽에서13829.76sin2(a)−461.3904−3031.2576cos(a)−4978.7136cos2(a)=0
삼각성을 사용하여 다시 쓰기
−461.3904+13829.76sin2(a)−3031.2576cos(a)−4978.7136cos2(a)
피타고라스 정체성 사용: cos2(x)+sin2(x)=1sin2(x)=1−cos2(x)=−461.3904+13829.76(1−cos2(a))−3031.2576cos(a)−4978.7136cos2(a)
−461.3904+13829.76(1−cos2(a))−3031.2576cos(a)−4978.7136cos2(a)간소화하다 :−18808.4736cos2(a)−3031.2576cos(a)+13368.3696
−461.3904+13829.76(1−cos2(a))−3031.2576cos(a)−4978.7136cos2(a)
13829.76(1−cos2(a))확대한다:13829.76−13829.76cos2(a)
13829.76(1−cos2(a))
분배 법칙 적용: a(b−c)=ab−aca=13829.76,b=1,c=cos2(a)=13829.76⋅1−13829.76cos2(a)
=1⋅13829.76−13829.76cos2(a)
숫자를 곱하시오: 1⋅13829.76=13829.76=13829.76−13829.76cos2(a)
=−461.3904+13829.76−13829.76cos2(a)−3031.2576cos(a)−4978.7136cos2(a)
−461.3904+13829.76−13829.76cos2(a)−3031.2576cos(a)−4978.7136cos2(a)단순화하세요:−18808.4736cos2(a)−3031.2576cos(a)+13368.3696
−461.3904+13829.76−13829.76cos2(a)−3031.2576cos(a)−4978.7136cos2(a)
집단적 용어=−13829.76cos2(a)−3031.2576cos(a)−4978.7136cos2(a)−461.3904+13829.76
유사 요소 추가: −13829.76cos2(a)−4978.7136cos2(a)=−18808.4736cos2(a)=−18808.4736cos2(a)−3031.2576cos(a)−461.3904+13829.76
숫자 더하기/ 빼기: −461.3904+13829.76=13368.3696=−18808.4736cos2(a)−3031.2576cos(a)+13368.3696
=−18808.4736cos2(a)−3031.2576cos(a)+13368.3696
=−18808.4736cos2(a)−3031.2576cos(a)+13368.3696
13368.3696−18808.4736cos2(a)−3031.2576cos(a)=0
대체로 해결
13368.3696−18808.4736cos2(a)−3031.2576cos(a)=0
하게: cos(a)=u13368.3696−18808.4736u2−3031.2576u=0
13368.3696−18808.4736u2−3031.2576u=0:u=−37616.94723031.2576+1014943029.424128,u=37616.94721014943029.424128−3031.2576
13368.3696−18808.4736u2−3031.2576u=0
표준 양식으로 작성 ax2+bx+c=0−18808.4736u2−3031.2576u+13368.3696=0
쿼드 공식으로 해결
−18808.4736u2−3031.2576u+13368.3696=0
4차 방정식 공식:
위해서 a=−18808.4736,b=−3031.2576,c=13368.3696u1,2=2(−18808.4736)−(−3031.2576)±(−3031.2576)2−4(−18808.4736)⋅13368.3696
u1,2=2(−18808.4736)−(−3031.2576)±(−3031.2576)2−4(−18808.4736)⋅13368.3696
(−3031.2576)2−4(−18808.4736)⋅13368.3696=1014943029.424128
(−3031.2576)2−4(−18808.4736)⋅13368.3696
규칙 적용 −(−a)=a=(−3031.2576)2+4⋅18808.4736⋅13368.3696
지수 규칙 적용: (−a)n=an,이면 n 균등하다(−3031.2576)2=3031.25762=3031.25762+4⋅13368.3696⋅18808.4736
숫자를 곱하시오: 4⋅18808.4736⋅13368.3696=1005754506.78657…=3031.25762+1005754506.78657…
3031.25762=9188522.63755…=9188522.63755…+1005754506.78657…
숫자 추가: 9188522.63755…+1005754506.78657…=1014943029.424128=1014943029.424128
u1,2=2(−18808.4736)−(−3031.2576)±1014943029.424128
솔루션 분리u1=2(−18808.4736)−(−3031.2576)+1014943029.424128,u2=2(−18808.4736)−(−3031.2576)−1014943029.424128
u=2(−18808.4736)−(−3031.2576)+1014943029.424128:−37616.94723031.2576+1014943029.424128
2(−18808.4736)−(−3031.2576)+1014943029.424128
괄호 제거: (−a)=−a,−(−a)=a=−2⋅18808.47363031.2576+1014943029.424128
숫자를 곱하시오: 2⋅18808.4736=37616.9472=−37616.94723031.2576+1014943029.424128
분수 규칙 적용: −ba=−ba=−37616.94723031.2576+1014943029.424128
u=2(−18808.4736)−(−3031.2576)−1014943029.424128:37616.94721014943029.424128−3031.2576
2(−18808.4736)−(−3031.2576)−1014943029.424128
괄호 제거: (−a)=−a,−(−a)=a=−2⋅18808.47363031.2576−1014943029.424128
숫자를 곱하시오: 2⋅18808.4736=37616.9472=−37616.94723031.2576−1014943029.424128
분수 규칙 적용: −b−a=ba3031.2576−1014943029.424128=−(1014943029.424128−3031.2576)=37616.94721014943029.424128−3031.2576
2차 방정식의 해는 다음과 같다:u=−37616.94723031.2576+1014943029.424128,u=37616.94721014943029.424128−3031.2576
뒤로 대체 u=cos(a)cos(a)=−37616.94723031.2576+1014943029.424128,cos(a)=37616.94721014943029.424128−3031.2576
cos(a)=−37616.94723031.2576+1014943029.424128,cos(a)=37616.94721014943029.424128−3031.2576
cos(a)=−37616.94723031.2576+1014943029.424128:a=arccos(−37616.94723031.2576+1014943029.424128)+2πn,a=−arccos(−37616.94723031.2576+1014943029.424128)+2πn
cos(a)=−37616.94723031.2576+1014943029.424128
트리거 역속성 적용
cos(a)=−37616.94723031.2576+1014943029.424128
일반 솔루션 cos(a)=−37616.94723031.2576+1014943029.424128cos(x)=−a⇒x=arccos(−a)+2πn,x=−arccos(−a)+2πna=arccos(−37616.94723031.2576+1014943029.424128)+2πn,a=−arccos(−37616.94723031.2576+1014943029.424128)+2πn
a=arccos(−37616.94723031.2576+1014943029.424128)+2πn,a=−arccos(−37616.94723031.2576+1014943029.424128)+2πn
cos(a)=37616.94721014943029.424128−3031.2576:a=arccos(37616.94721014943029.424128−3031.2576)+2πn,a=2π−arccos(37616.94721014943029.424128−3031.2576)+2πn
cos(a)=37616.94721014943029.424128−3031.2576
트리거 역속성 적용
cos(a)=37616.94721014943029.424128−3031.2576
일반 솔루션 cos(a)=37616.94721014943029.424128−3031.2576cos(x)=a⇒x=arccos(a)+2πn,x=2π−arccos(a)+2πna=arccos(37616.94721014943029.424128−3031.2576)+2πn,a=2π−arccos(37616.94721014943029.424128−3031.2576)+2πn
a=arccos(37616.94721014943029.424128−3031.2576)+2πn,a=2π−arccos(37616.94721014943029.424128−3031.2576)+2πn
모든 솔루션 결합a=arccos(−37616.94723031.2576+1014943029.424128)+2πn,a=−arccos(−37616.94723031.2576+1014943029.424128)+2πn,a=arccos(37616.94721014943029.424128−3031.2576)+2πn,a=2π−arccos(37616.94721014943029.424128−3031.2576)+2πn
해법을 원래 방정식에 연결하여 검증
솔루션을 에 연결하여 확인합니다 129.8sin(a)−0.6129.8cos(a)=121.79
방정식에 맞지 않는 것은 제거하십시오.
솔루션 확인 arccos(−37616.94723031.2576+1014943029.424128)+2πn:거짓
arccos(−37616.94723031.2576+1014943029.424128)+2πn
n=1끼우다 arccos(−37616.94723031.2576+1014943029.424128)+2π1
129.8sin(a)−0.6129.8cos(a)=121.79 위한 {\ quad}끼우다{\ quad} a=arccos(−37616.94723031.2576+1014943029.424128)+2π112⋅9.8sin(arccos(−37616.94723031.2576+1014943029.424128)+2π1)−0.6⋅12⋅9.8cos(arccos(−37616.94723031.2576+1014943029.424128)+2π1)=12⋅1.79
다듬다109.40771…=21.48
⇒거짓
솔루션 확인 −arccos(−37616.94723031.2576+1014943029.424128)+2πn:참
−arccos(−37616.94723031.2576+1014943029.424128)+2πn
n=1끼우다 −arccos(−37616.94723031.2576+1014943029.424128)+2π1
129.8sin(a)−0.6129.8cos(a)=121.79 위한 {\ quad}끼우다{\ quad} a=−arccos(−37616.94723031.2576+1014943029.424128)+2π112⋅9.8sin(−arccos(−37616.94723031.2576+1014943029.424128)+2π1)−0.6⋅12⋅9.8cos(−arccos(−37616.94723031.2576+1014943029.424128)+2π1)=12⋅1.79
다듬다21.48=21.48
⇒참
솔루션 확인 arccos(37616.94721014943029.424128−3031.2576)+2πn:참
arccos(37616.94721014943029.424128−3031.2576)+2πn
n=1끼우다 arccos(37616.94721014943029.424128−3031.2576)+2π1
129.8sin(a)−0.6129.8cos(a)=121.79 위한 {\ quad}끼우다{\ quad} a=arccos(37616.94721014943029.424128−3031.2576)+2π112⋅9.8sin(arccos(37616.94721014943029.424128−3031.2576)+2π1)−0.6⋅12⋅9.8cos(arccos(37616.94721014943029.424128−3031.2576)+2π1)=12⋅1.79
다듬다21.48=21.48
⇒참
솔루션 확인 2π−arccos(37616.94721014943029.424128−3031.2576)+2πn:거짓
2π−arccos(37616.94721014943029.424128−3031.2576)+2πn
n=1끼우다 2π−arccos(37616.94721014943029.424128−3031.2576)+2π1
129.8sin(a)−0.6129.8cos(a)=121.79 위한 {\ quad}끼우다{\ quad} a=2π−arccos(37616.94721014943029.424128−3031.2576)+2π112⋅9.8sin(2π−arccos(37616.94721014943029.424128−3031.2576)+2π1)−0.6⋅12⋅9.8cos(2π−arccos(37616.94721014943029.424128−3031.2576)+2π1)=12⋅1.79
다듬다−129.62418…=21.48
⇒거짓
a=−arccos(−37616.94723031.2576+1014943029.424128)+2πn,a=arccos(37616.94721014943029.424128−3031.2576)+2πn
해를 10진수 형식으로 표시a=−2.75844…+2πn,a=0.69769…+2πn