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受欢迎的三角函数 >

cos(x)= 1/(sqrt(37))

解答

cos (x) = \frac{1}{37}

解答

x = 1.40564 \dots + 2 πn, x = 2 π - 1.40564 \dots + 2 πn

+1

弧度

x = 1.40564 \dots + 6.28318 \dots n, x = 4.87753 \dots + 6.28318 \dots n

求解步骤

cos (x) = \frac{1}{37}

化简

\frac{1}{37} : \frac{37}{37}

\frac{1}{37}

乘以共轭根式

\frac{37}{37}

= \frac{1 \cdot 37}{37 37}

1 \cdot 37 = 37

3737 = 37

3737

使用根式运算法则:

a a = a

3737 = 37

= 37

= \frac{37}{37}

cos (x) = \frac{37}{37}

使用反三角函数性质

cos (x) = \frac{37}{37}

cos (x) = \frac{37}{37}

的通解

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{37}{37}) + 2 πn, x = 2 π - arccos (\frac{37}{37}) + 2 πn

x = arccos (\frac{37}{37}) + 2 πn, x = 2 π - arccos (\frac{37}{37}) + 2 πn

以小数形式表示解

x = 1.40564 \dots + 2 πn, x = 2 π - 1.40564 \dots + 2 πn

作图

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