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受欢迎的三角函数 >

1/((sec^2(a)))+1/((cos^2(a)))=1

解答

\frac{1}{( sec ^{2} ( a ) )} + \frac{1}{( cos ^{2} ( a ) )} = 1

解答

a \in R 无解

求解步骤

\frac{1}{( sec ^{2} ( a ) )} + \frac{1}{( cos ^{2} ( a ) )} = 1

两边减去

1

\frac{1}{sec ^{2} ( a )} + \frac{1}{cos ^{2} ( a )} - 1 = 0

化简

\frac{1}{sec ^{2} ( a )} + \frac{1}{cos ^{2} ( a )} - 1 : \frac{cos ^{2} ( a ) + sec ^{2} ( a ) - sec ^{2} ( a ) cos ^{2} ( a )}{sec ^{2} ( a ) cos ^{2} ( a )}

\frac{1}{sec ^{2} ( a )} + \frac{1}{cos ^{2} ( a )} - 1

将项转换为分式:

1 = \frac{1}{1}

= \frac{1}{sec ^{2} ( a )} + \frac{1}{cos ^{2} ( a )} - \frac{1}{1}

sec^{2} (a), cos^{2} (a), 1

的最小公倍数:

sec^{2} (a) cos^{2} (a)

sec^{2} (a), cos^{2} (a), 1

最小公倍数 (LCM)

计算出由至少在以下一个因式表达式中出现的因子组成的表达式

= sec^{2} (a) cos^{2} (a)

根据最小公倍数调整分式

将每个分子乘以其分母转变为最小公倍数所要乘以的同一数值

sec^{2} (a) cos^{2} (a)

对于

\frac{1}{sec ^{2} ( a )} :

将分母和分子乘以

cos^{2} (a)

\frac{1}{sec ^{2} ( a )} = \frac{1 \cdot cos ^{2} ( a )}{sec ^{2} ( a ) cos ^{2} ( a )} = \frac{cos ^{2} ( a )}{sec ^{2} ( a ) cos ^{2} ( a )}

对于

\frac{1}{cos ^{2} ( a )} :

将分母和分子乘以

sec^{2} (a)

\frac{1}{cos ^{2} ( a )} = \frac{1 \cdot sec ^{2} ( a )}{cos ^{2} ( a ) sec ^{2} ( a )} = \frac{sec ^{2} ( a )}{sec ^{2} ( a ) cos ^{2} ( a )}

对于

\frac{1}{1} :

将分母和分子乘以

sec^{2} (a) cos^{2} (a)

\frac{1}{1} = \frac{1 \cdot sec ^{2} ( a ) cos ^{2} ( a )}{1 \cdot sec ^{2} ( a ) cos ^{2} ( a )} = \frac{sec ^{2} ( a ) cos ^{2} ( a )}{sec ^{2} ( a ) cos ^{2} ( a )}

= \frac{cos ^{2} ( a )}{sec ^{2} ( a ) cos ^{2} ( a )} + \frac{sec ^{2} ( a )}{sec ^{2} ( a ) cos ^{2} ( a )} - \frac{sec ^{2} ( a ) cos ^{2} ( a )}{sec ^{2} ( a ) cos ^{2} ( a )}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{cos ^{2} ( a ) + sec ^{2} ( a ) - sec ^{2} ( a ) cos ^{2} ( a )}{sec ^{2} ( a ) cos ^{2} ( a )}

\frac{cos ^{2} ( a ) + sec ^{2} ( a ) - sec ^{2} ( a ) cos ^{2} ( a )}{sec ^{2} ( a ) cos ^{2} ( a )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

cos^{2} (a) + sec^{2} (a) - sec^{2} (a) cos^{2} (a) = 0

使用三角恒等式改写

cos^{2} (a) + sec^{2} (a) - cos^{2} (a) sec^{2} (a)

使用基本三角恒等式:

cos (x) = \frac{1}{sec ( x )}

= (\frac{1}{sec ( a )})^{2} + sec^{2} (a) - (\frac{1}{sec ( a )})^{2} sec^{2} (a)

化简

(\frac{1}{sec ( a )})^{2} + sec^{2} (a) - (\frac{1}{sec ( a )})^{2} sec^{2} (a) : \frac{1}{sec ^{2} ( a )} + sec^{2} (a) - 1

(\frac{1}{sec ( a )})^{2} + sec^{2} (a) - (\frac{1}{sec ( a )})^{2} sec^{2} (a)

(\frac{1}{sec ( a )})^{2} = \frac{1}{sec ^{2} ( a )}

(\frac{1}{sec ( a )})^{2}

使用指数法则:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{sec ^{2} ( a )}

使用法则

1^{a} = 1

1^{2} = 1

= \frac{1}{sec ^{2} ( a )}

(\frac{1}{sec ( a )})^{2} sec^{2} (a) = 1

(\frac{1}{sec ( a )})^{2} sec^{2} (a)

(\frac{1}{sec ( a )})^{2} = \frac{1}{sec ^{2} ( a )}

(\frac{1}{sec ( a )})^{2}

使用指数法则:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{sec ^{2} ( a )}

使用法则

1^{a} = 1

1^{2} = 1

= \frac{1}{sec ^{2} ( a )}

= \frac{1}{sec ^{2} ( a )} sec^{2} (a)

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot sec ^{2} ( a )}{sec ^{2} ( a )}

约分:

sec^{2} (a)

= 1

= \frac{1}{sec ^{2} ( a )} + sec^{2} (a) - 1

= \frac{1}{sec ^{2} ( a )} + sec^{2} (a) - 1

- 1 + \frac{1}{sec ^{2} ( a )} + sec^{2} (a) = 0

用替代法求解

- 1 + \frac{1}{sec ^{2} ( a )} + sec^{2} (a) = 0

令

: sec (a) = u

- 1 + \frac{1}{u ^{2}} + u^{2} = 0

- 1 + \frac{1}{u ^{2}} + u^{2} = 0 : u = \frac{3}{2} + \frac{1}{2} i, u = - \frac{3}{2} - \frac{1}{2} i, u = - \frac{3}{2} + \frac{1}{2} i, u = \frac{3}{2} - \frac{1}{2} i

- 1 + \frac{1}{u ^{2}} + u^{2} = 0

在两边乘以

u^{2}

- 1 + \frac{1}{u ^{2}} + u^{2} = 0

在两边乘以

u^{2}

- 1 \cdot u^{2} + \frac{1}{u ^{2}} u^{2} + u^{2} u^{2} = 0 \cdot u^{2}

化简

- 1 \cdot u^{2} + \frac{1}{u ^{2}} u^{2} + u^{2} u^{2} = 0 \cdot u^{2}

化简

- 1 \cdot u^{2} : - u^{2}

- 1 \cdot u^{2}

乘以:

1 \cdot u^{2} = u^{2}

= - u^{2}

化简

\frac{1}{u ^{2}} u^{2} : 1

\frac{1}{u ^{2}} u^{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot u ^{2}}{u ^{2}}

约分:

u^{2}

= 1

化简

u^{2} u^{2} : u^{4}

u^{2} u^{2}

使用指数法则:

a^{b} \cdot a^{c} = a^{b + c}

u^{2} u^{2} = u^{2 + 2}

= u^{2 + 2}

数字相加:

2 + 2 = 4

= u^{4}

化简

0 \cdot u^{2} : 0

0 \cdot u^{2}

使用法则

0 \cdot a = 0

= 0

- u^{2} + 1 + u^{4} = 0

- u^{2} + 1 + u^{4} = 0

- u^{2} + 1 + u^{4} = 0

解

- u^{2} + 1 + u^{4} = 0 : u = \frac{3}{2} + \frac{1}{2} i, u = - \frac{3}{2} - \frac{1}{2} i, u = - \frac{3}{2} + \frac{1}{2} i, u = \frac{3}{2} - \frac{1}{2} i

- u^{2} + 1 + u^{4} = 0

改写成标准形式

a_{n} x^{n} + \dots + a_{1} x + a = 0

u^{4} - u^{2} + 1 = 0

用

x = u^{2}

和

x^{2} = u^{4}

改写方程式

x^{2} - x + 1 = 0

解

x^{2} - x + 1 = 0 : x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

x^{2} - x + 1 = 0

使用求根公式求解

x^{2} - x + 1 = 0

二次方程求根公式:

若

a = 1, b = - 1, c = 1

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

化简

(- 1)^{2} - 4 \cdot 1 \cdot 1 : 3 i

(- 1)^{2} - 4 \cdot 1 \cdot 1

(- 1)^{2} = 1

(- 1)^{2}

使用指数法则:

(- a)^{n} = a^{n},

若

n

是偶数

(- 1)^{2} = 1^{2}

= 1^{2}

使用法则

1^{a} = 1

= 1

4 \cdot 1 \cdot 1 = 4

4 \cdot 1 \cdot 1

数字相乘:

4 \cdot 1 \cdot 1 = 4

= 4

= 1 - 4

数字相减:

1 - 4 = - 3

= - 3

使用根式运算法则:

- a = - 1 a

- 3 = - 1 3

= - 1 3

使用虚数运算法则:

- 1 = i

= 3 i

x_{1, 2} = \frac{- ( - 1 ) \pm 3 i}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( - 1 ) + 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3 i}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3 i}{2 \cdot 1} : \frac{1}{2} + i \frac{3}{2}

\frac{- ( - 1 ) + 3 i}{2 \cdot 1}

使用法则

- (- a) = a

= \frac{1 + 3 i}{2 \cdot 1}

数字相乘:

2 \cdot 1 = 2

= \frac{1 + 3 i}{2}

将

\frac{1 + 3 i}{2}

改写成标准复数形式:

\frac{1}{2} + \frac{3}{2} i

\frac{1 + 3 i}{2}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1 + 3 i}{2} = \frac{1}{2} + \frac{3 i}{2}

= \frac{1}{2} + \frac{3 i}{2}

= \frac{1}{2} + \frac{3}{2} i

x = \frac{- ( - 1 ) - 3 i}{2 \cdot 1} : \frac{1}{2} - i \frac{3}{2}

\frac{- ( - 1 ) - 3 i}{2 \cdot 1}

使用法则

- (- a) = a

= \frac{1 - 3 i}{2 \cdot 1}

数字相乘:

2 \cdot 1 = 2

= \frac{1 - 3 i}{2}

将

\frac{1 - 3 i}{2}

改写成标准复数形式:

\frac{1}{2} - \frac{3}{2} i

\frac{1 - 3 i}{2}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1 - 3 i}{2} = \frac{1}{2} - \frac{3 i}{2}

= \frac{1}{2} - \frac{3 i}{2}

= \frac{1}{2} - \frac{3}{2} i

二次方程组的解是:

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

代回

x = u^{2}

，求解

u

解

u^{2} = \frac{1}{2} + i \frac{3}{2} : u = \frac{3}{2} + \frac{1}{2} i, u = - \frac{3}{2} - \frac{1}{2} i

u^{2} = \frac{1}{2} + i \frac{3}{2}

替代

u = x + y i

(x + y i)^{2} = \frac{1}{2} + i \frac{3}{2}

展开

(x + y i)^{2} : (x^{2} - y^{2}) + 2 i x y

(x + y i)^{2}

= (x + i y)^{2}

使用完全平方公式:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = x, b = y i

= x^{2} + 2 x y i + (y i)^{2}

(y i)^{2} = - y^{2}

(y i)^{2}

使用指数法则:

(a \cdot b)^{n} = a^{n} b^{n}

= i^{2} y^{2}

i^{2} = - 1

i^{2}

使用虚数运算法则:

i^{2} = - 1

= - 1

= (- 1) y^{2}

整理后得

= - y^{2}

= x^{2} + 2 i x y - y^{2}

将

x^{2} + 2 i x y - y^{2}

改写成标准复数形式:

(x^{2} - y^{2}) + 2 x y i

x^{2} + 2 i x y - y^{2}

将复数的实部和虚部分组

= (x^{2} - y^{2}) + 2 x y i

= (x^{2} - y^{2}) + 2 x y i

(x^{2} - y^{2}) + 2 i x y = \frac{1}{2} + i \frac{3}{2}

复数仅在实部和虚部均相等时才相等改写为方程组:

[x^{2} - y^{2} = \frac{1}{2} 2 x y = \frac{3}{2}]

[x^{2} - y^{2} = \frac{1}{2} 2 x y = \frac{3}{2}] : (x = \frac{3}{2}, x = - \frac{3}{2}, y = \frac{1}{2} y = - \frac{1}{2})

[x^{2} - y^{2} = \frac{1}{2} 2 x y = \frac{3}{2}]

对于

2 x y = \frac{3}{2}

将

x

移到一边:

x = \frac{3}{4 y}

2 x y = \frac{3}{2}

两边除以

2 y

2 x y = \frac{3}{2}

两边除以

2 y

\frac{2 x y}{2 y} = \frac{\frac{3}{2}}{2 y}

化简

\frac{2 x y}{2 y} = \frac{\frac{3}{2}}{2 y}

化简

\frac{2 x y}{2 y} : x

\frac{2 x y}{2 y}

数字相除:

\frac{2}{2} = 1

= \frac{x y}{y}

约分:

y

= x

化简

\frac{\frac{3}{2}}{2 y} : \frac{3}{4 y}

\frac{\frac{3}{2}}{2 y}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3}{2 \cdot 2 y}

数字相乘:

2 \cdot 2 = 4

= \frac{3}{4 y}

x = \frac{3}{4 y}

x = \frac{3}{4 y}

x = \frac{3}{4 y}

将解

x = \frac{3}{4 y}

代入

x^{2} - y^{2} = \frac{1}{2}

对于

x^{2} - y^{2} = \frac{1}{2}

，用

\frac{3}{4 y}

替代

x : y = \frac{1}{2}, y = - \frac{1}{2}

对于

x^{2} - y^{2} = \frac{1}{2}

，用

\frac{3}{4 y}

替代

x

(\frac{3}{4 y})^{2} - y^{2} = \frac{1}{2}

解

(\frac{3}{4 y})^{2} - y^{2} = \frac{1}{2} : y = \frac{1}{2}, y = - \frac{1}{2}

(\frac{3}{4 y})^{2} - y^{2} = \frac{1}{2}

乘以最小公倍数

(\frac{3}{4 y})^{2} - y^{2} = \frac{1}{2}

化简

(\frac{3}{4 y})^{2} : \frac{3}{16 y ^{2}}

(\frac{3}{4 y})^{2}

使用指数法则:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 3 ) ^{2}}{( 4 y ) ^{2}}

使用指数法则:

(a \cdot b)^{n} = a^{n} b^{n}

(4 y)^{2} = 4^{2} y^{2}

= \frac{( 3 ) ^{2}}{4 ^{2} y ^{2}}

(3)^{2} : 3

使用根式运算法则:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

使用指数法则:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

约分:

2

= 1

= 3

= \frac{3}{4 ^{2} y ^{2}}

4^{2} = 16

= \frac{3}{16 y ^{2}}

\frac{3}{16 y ^{2}} - y^{2} = \frac{1}{2}

找到

16 y^{2}, 2

的最小公倍数:

16 y^{2}

16 y^{2}, 2

最小公倍数 (LCM)

16, 2

的最小公倍数:

16

16, 2

最小公倍数 (LCM)

16

质因数分解:

2 \cdot 2 \cdot 2 \cdot 2

16

16

除以

216 = 8 \cdot 2

= 2 \cdot 8

8

除以

28 = 4 \cdot 2

= 2 \cdot 2 \cdot 4

4

除以

24 = 2 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2

2

质因数分解:

2

2

2

是质数，因此无法因数分解

= 2

将每个因子乘以它在

16

或

2

中出现的最多次数

= 2 \cdot 2 \cdot 2 \cdot 2

数字相乘:

2 \cdot 2 \cdot 2 \cdot 2 = 16

= 16

计算出由出现在

16 y^{2}

或

2

中的因子组成的表达式

= 16 y^{2}

乘以最小公倍数=

16 y^{2}

\frac{3}{16 y ^{2}} \cdot 16 y^{2} - y^{2} \cdot 16 y^{2} = \frac{1}{2} \cdot 16 y^{2}

化简

\frac{3}{16 y ^{2}} \cdot 16 y^{2} - y^{2} \cdot 16 y^{2} = \frac{1}{2} \cdot 16 y^{2}

化简

\frac{3}{16 y ^{2}} \cdot 16 y^{2} : 3

\frac{3}{16 y ^{2}} \cdot 16 y^{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 \cdot 16 y ^{2}}{16 y ^{2}}

约分:

16

= \frac{3 y ^{2}}{y ^{2}}

约分:

y^{2}

= 3

化简

- y^{2} \cdot 16 y^{2} : - 16 y^{4}

- y^{2} \cdot 16 y^{2}

使用指数法则:

a^{b} \cdot a^{c} = a^{b + c}

y^{2} y^{2} = y^{2 + 2}

= - 16 y^{2 + 2}

数字相加:

2 + 2 = 4

= - 16 y^{4}

化简

\frac{1}{2} \cdot 16 y^{2} : 8 y^{2}

\frac{1}{2} \cdot 16 y^{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 16}{2} y^{2}

\frac{1 \cdot 16}{2} = 8

\frac{1 \cdot 16}{2}

数字相乘:

1 \cdot 16 = 16

= \frac{16}{2}

数字相除:

\frac{16}{2} = 8

= 8

= 8 y^{2}

3 - 16 y^{4} = 8 y^{2}

3 - 16 y^{4} = 8 y^{2}

3 - 16 y^{4} = 8 y^{2}

解

3 - 16 y^{4} = 8 y^{2} : y = \frac{1}{2}, y = - \frac{1}{2}

3 - 16 y^{4} = 8 y^{2}

将

8 y^{2}

para o lado esquerdo

3 - 16 y^{4} = 8 y^{2}

两边减去

8 y^{2}

3 - 16 y^{4} - 8 y^{2} = 8 y^{2} - 8 y^{2}

化简

3 - 16 y^{4} - 8 y^{2} = 0

3 - 16 y^{4} - 8 y^{2} = 0

改写成标准形式

a_{n} x^{n} + \dots + a_{1} x + a = 0

- 16 y^{4} - 8 y^{2} + 3 = 0

用

u = y^{2}

和

u^{2} = y^{4}

改写方程式

- 16 u^{2} - 8 u + 3 = 0

解

- 16 u^{2} - 8 u + 3 = 0 : u = - \frac{3}{4}, u = \frac{1}{4}

- 16 u^{2} - 8 u + 3 = 0

使用求根公式求解

- 16 u^{2} - 8 u + 3 = 0

二次方程求根公式:

若

a = - 16, b = - 8, c = 3

u_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 16 ) \cdot 3}{2 ( - 16 )}

u_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 16 ) \cdot 3}{2 ( - 16 )}

(- 8)^{2} - 4 (- 16) \cdot 3 = 16

(- 8)^{2} - 4 (- 16) \cdot 3

使用法则

- (- a) = a

= (- 8)^{2} + 4 \cdot 16 \cdot 3

使用指数法则:

(- a)^{n} = a^{n},

若

n

是偶数

(- 8)^{2} = 8^{2}

= 8^{2} + 4 \cdot 16 \cdot 3

数字相乘:

4 \cdot 16 \cdot 3 = 192

= 8^{2} + 192

8^{2} = 64

= 64 + 192

数字相加:

64 + 192 = 256

= 256

因式分解数字:

256 = 1 6^{2}

= 1 6^{2}

使用根式运算法则:

n a^{n} = a

1 6^{2} = 16

= 16

u_{1, 2} = \frac{- ( - 8 ) \pm 16}{2 ( - 16 )}

将解分隔开

u_{1} = \frac{- ( - 8 ) + 16}{2 ( - 16 )}, u_{2} = \frac{- ( - 8 ) - 16}{2 ( - 16 )}

u = \frac{- ( - 8 ) + 16}{2 ( - 16 )} : - \frac{3}{4}

\frac{- ( - 8 ) + 16}{2 ( - 16 )}

去除括号:

(- a) = - a, - (- a) = a

= \frac{8 + 16}{- 2 \cdot 16}

数字相加:

8 + 16 = 24

= \frac{24}{- 2 \cdot 16}

数字相乘:

2 \cdot 16 = 32

= \frac{24}{- 32}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{24}{32}

约分:

8

= - \frac{3}{4}

u = \frac{- ( - 8 ) - 16}{2 ( - 16 )} : \frac{1}{4}

\frac{- ( - 8 ) - 16}{2 ( - 16 )}

去除括号:

(- a) = - a, - (- a) = a

= \frac{8 - 16}{- 2 \cdot 16}

数字相减:

8 - 16 = - 8

= \frac{- 8}{- 2 \cdot 16}

数字相乘:

2 \cdot 16 = 32

= \frac{- 8}{- 32}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{8}{32}

约分:

8

= \frac{1}{4}

二次方程组的解是:

u = - \frac{3}{4}, u = \frac{1}{4}

u = - \frac{3}{4}, u = \frac{1}{4}

代回

u = y^{2}

，求解

y

解

y^{2} = - \frac{3}{4} : y \in R

无解

y^{2} = - \frac{3}{4}

x^{2}

在

x

内不能为负

\in R

y \in R 无解

解

y^{2} = \frac{1}{4} : y = \frac{1}{2}, y = - \frac{1}{2}

y^{2} = \frac{1}{4}

对于

x^{2} = f (a)

解为

x = f (a), - f (a)

y = \frac{1}{4}, y = - \frac{1}{4}

\frac{1}{4} = \frac{1}{2}

\frac{1}{4}

使用根式运算法则:

\frac{a}{b} = \frac{a}{b}, a \geq 0, b \geq 0

= \frac{1}{4}

使用根式运算法则:

1 = 1

1 = 1

= \frac{1}{4}

4 = 2

4

因式分解数字:

4 = 2^{2}

= 2^{2}

使用根式运算法则:

a^{2} = a, a \geq 0

2^{2} = 2

= 2

= \frac{1}{2}

- \frac{1}{4} = - \frac{1}{2}

- \frac{1}{4}

使用根式运算法则:

\frac{a}{b} = \frac{a}{b}, a \geq 0, b \geq 0

= - \frac{1}{4}

使用根式运算法则:

1 = 1

1 = 1

= - \frac{1}{4}

4 = 2

4

因式分解数字:

4 = 2^{2}

= 2^{2}

使用根式运算法则:

a^{2} = a, a \geq 0

2^{2} = 2

= 2

= - \frac{1}{2}

y = \frac{1}{2}, y = - \frac{1}{2}

解为

y = \frac{1}{2}, y = - \frac{1}{2}

y = \frac{1}{2}, y = - \frac{1}{2}

验证解

找到无定义的点（奇点）:

y = 0

取

(\frac{3}{4 y})^{2} - y^{2}

的分母，令其等于零

解

4 y = 0 : y = 0

4 y = 0

两边除以

4

4 y = 0

两边除以

4

\frac{4 y}{4} = \frac{0}{4}

化简

y = 0

y = 0

以下点无定义

y = 0

将不在定义域的点与解相综合:

y = \frac{1}{2}, y = - \frac{1}{2}

将解

y = \frac{1}{2}, y = - \frac{1}{2}

代入

2 x y = \frac{3}{2}

对于

2 x y = \frac{3}{2}

，用

\frac{1}{2}

替代

y : x = \frac{3}{2}

对于

2 x y = \frac{3}{2}

，用

\frac{1}{2}

替代

y

2 x \frac{1}{2} = \frac{3}{2}

解

2 x \frac{1}{2} = \frac{3}{2} : x = \frac{3}{2}

2 x \frac{1}{2} = \frac{3}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

\frac{1 \cdot 2}{2} x = \frac{3}{2}

约分:

2

x \cdot 1 = \frac{3}{2}

乘以:

x \cdot 1 = x

x = \frac{3}{2}

对于

2 x y = \frac{3}{2}

，用

- \frac{1}{2}

替代

y : x = - \frac{3}{2}

对于

2 x y = \frac{3}{2}

，用

- \frac{1}{2}

替代

y

2 x (- \frac{1}{2}) = \frac{3}{2}

解

2 x (- \frac{1}{2}) = \frac{3}{2} : x = - \frac{3}{2}

2 x (- \frac{1}{2}) = \frac{3}{2}

两边除以

2 (- \frac{1}{2})

2 x (- \frac{1}{2}) = \frac{3}{2}

两边除以

2 (- \frac{1}{2})

\frac{2 x ( - \frac{1}{2} )}{2 ( - \frac{1}{2} )} = \frac{\frac{3}{2}}{2 ( - \frac{1}{2} )}

化简

\frac{2 x ( - \frac{1}{2} )}{2 ( - \frac{1}{2} )} = \frac{\frac{3}{2}}{2 ( - \frac{1}{2} )}

化简

\frac{2 x ( - \frac{1}{2} )}{2 ( - \frac{1}{2} )} : x

\frac{2 x ( - \frac{1}{2} )}{2 ( - \frac{1}{2} )}

去除括号:

(- a) = - a

= \frac{- 2 x \frac{1}{2}}{- 2 \cdot \frac{1}{2}}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{2 x \frac{1}{2}}{2 \cdot \frac{1}{2}}

乘

2 x \frac{1}{2} : x

2 x \frac{1}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2 x}{2}

约分:

2

= 1 \cdot x

乘以:

1 \cdot x = x

= x

= \frac{x}{2 \cdot \frac{1}{2}}

乘

2 \cdot \frac{1}{2} : 1

2 \cdot \frac{1}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

约分:

2

= 1

= \frac{x}{1}

使用法则

\frac{a}{1} = a

= x

化简

\frac{\frac{3}{2}}{2 ( - \frac{1}{2} )} : - \frac{3}{2}

\frac{\frac{3}{2}}{2 ( - \frac{1}{2} )}

去除括号:

(- a) = - a

= \frac{\frac{3}{2}}{- 2 \cdot \frac{1}{2}}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{\frac{3}{2}}{2 \cdot \frac{1}{2}}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

\frac{\frac{3}{2}}{2 \cdot \frac{1}{2}} = \frac{3}{2 \cdot 2 \cdot \frac{1}{2}}

= - \frac{3}{2 \cdot 2 \cdot \frac{1}{2}}

数字相乘:

2 \cdot 2 = 4

= - \frac{3}{4 \cdot \frac{1}{2}}

乘

4 \cdot \frac{1}{2} : 2

4 \cdot \frac{1}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 4}{2}

数字相乘:

1 \cdot 4 = 4

= \frac{4}{2}

数字相除:

\frac{4}{2} = 2

= 2

= - \frac{3}{2}

x = - \frac{3}{2}

x = - \frac{3}{2}

x = - \frac{3}{2}

将解代入原方程进行验证

将它们代入

x^{2} - y^{2} = \frac{1}{2}

检验解是否符合

去除与方程不符的解。

检验

x = - \frac{3}{2}, y = - \frac{1}{2}

的解:

真

x^{2} - y^{2} = \frac{1}{2}

代入

x = - \frac{3}{2}, y = - \frac{1}{2}

(- \frac{3}{2})^{2} - (- \frac{1}{2})^{2} = \frac{1}{2}

整理后得

\frac{1}{2} = \frac{1}{2}

真

检验

x = \frac{3}{2}, y = \frac{1}{2}

的解:

真

x^{2} - y^{2} = \frac{1}{2}

代入

x = \frac{3}{2}, y = \frac{1}{2}

(\frac{3}{2})^{2} - (\frac{1}{2})^{2} = \frac{1}{2}

整理后得

\frac{1}{2} = \frac{1}{2}

真

将它们代入

2 x y = \frac{3}{2}

检验解是否符合

去除与方程不符的解。

检验

x = - \frac{3}{2}, y = - \frac{1}{2}

的解:

真

2 x y = \frac{3}{2}

代入

x = - \frac{3}{2}, y = - \frac{1}{2}

2 (- \frac{3}{2}) (- \frac{1}{2}) = \frac{3}{2}

整理后得

\frac{3}{2} = \frac{3}{2}

真

检验

x = \frac{3}{2}, y = \frac{1}{2}

的解:

真

2 x y = \frac{3}{2}

代入

x = \frac{3}{2}, y = \frac{1}{2}

2 \cdot \frac{3}{2} \cdot \frac{1}{2} = \frac{3}{2}

整理后得

\frac{3}{2} = \frac{3}{2}

真

因而，

x^{2} - y^{2} = \frac{1}{2}, 2 x y = \frac{3}{2}

最后的解是

(x = \frac{3}{2}, x = - \frac{3}{2}, y = \frac{1}{2} y = - \frac{1}{2})

u = x + y i

代回

u = \frac{3}{2} + \frac{1}{2} i, u = - \frac{3}{2} - \frac{1}{2} i

解

u^{2} = \frac{1}{2} - i \frac{3}{2} : u = - \frac{3}{2} + \frac{1}{2} i, u = \frac{3}{2} - \frac{1}{2} i

u^{2} = \frac{1}{2} - i \frac{3}{2}

替代

u = x + y i

(x + y i)^{2} = \frac{1}{2} - i \frac{3}{2}

展开

(x + y i)^{2} : (x^{2} - y^{2}) + 2 i x y

(x + y i)^{2}

= (x + i y)^{2}

使用完全平方公式:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = x, b = y i

= x^{2} + 2 x y i + (y i)^{2}

(y i)^{2} = - y^{2}

(y i)^{2}

使用指数法则:

(a \cdot b)^{n} = a^{n} b^{n}

= i^{2} y^{2}

i^{2} = - 1

i^{2}

使用虚数运算法则:

i^{2} = - 1

= - 1

= (- 1) y^{2}

整理后得

= - y^{2}

= x^{2} + 2 i x y - y^{2}

将

x^{2} + 2 i x y - y^{2}

改写成标准复数形式:

(x^{2} - y^{2}) + 2 x y i

x^{2} + 2 i x y - y^{2}

将复数的实部和虚部分组

= (x^{2} - y^{2}) + 2 x y i

= (x^{2} - y^{2}) + 2 x y i

(x^{2} - y^{2}) + 2 i x y = \frac{1}{2} - i \frac{3}{2}

复数仅在实部和虚部均相等时才相等改写为方程组:

[x^{2} - y^{2} = \frac{1}{2} 2 x y = - \frac{3}{2}]

[x^{2} - y^{2} = \frac{1}{2} 2 x y = - \frac{3}{2}] : (x = - \frac{3}{2}, x = \frac{3}{2}, y = \frac{1}{2} y = - \frac{1}{2})

[x^{2} - y^{2} = \frac{1}{2} 2 x y = - \frac{3}{2}]

对于

2 x y = - \frac{3}{2}

将

x

移到一边:

x = - \frac{3}{4 y}

2 x y = - \frac{3}{2}

两边除以

2 y

2 x y = - \frac{3}{2}

两边除以

2 y

\frac{2 x y}{2 y} = \frac{- \frac{3}{2}}{2 y}

化简

\frac{2 x y}{2 y} = \frac{- \frac{3}{2}}{2 y}

化简

\frac{2 x y}{2 y} : x

\frac{2 x y}{2 y}

数字相除:

\frac{2}{2} = 1

= \frac{x y}{y}

约分:

y

= x

化简

\frac{- \frac{3}{2}}{2 y} : - \frac{3}{4 y}

\frac{- \frac{3}{2}}{2 y}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{\frac{3}{2}}{2 y}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

\frac{\frac{3}{2}}{2 y} = \frac{3}{2 \cdot 2 y}

= - \frac{3}{2 \cdot 2 y}

数字相乘:

2 \cdot 2 = 4

= - \frac{3}{4 y}

x = - \frac{3}{4 y}

x = - \frac{3}{4 y}

x = - \frac{3}{4 y}

将解

x = - \frac{3}{4 y}

代入

x^{2} - y^{2} = \frac{1}{2}

对于

x^{2} - y^{2} = \frac{1}{2}

，用

- \frac{3}{4 y}

替代

x : y = \frac{1}{2}, y = - \frac{1}{2}

对于

x^{2} - y^{2} = \frac{1}{2}

，用

- \frac{3}{4 y}

替代

x

(- \frac{3}{4 y})^{2} - y^{2} = \frac{1}{2}

解

(- \frac{3}{4 y})^{2} - y^{2} = \frac{1}{2} : y = \frac{1}{2}, y = - \frac{1}{2}

(- \frac{3}{4 y})^{2} - y^{2} = \frac{1}{2}

乘以最小公倍数

(- \frac{3}{4 y})^{2} - y^{2} = \frac{1}{2}

化简

(- \frac{3}{4 y})^{2} : \frac{3}{16 y ^{2}}

(- \frac{3}{4 y})^{2}

使用指数法则:

(- a)^{n} = a^{n},

若

n

是偶数

(- \frac{3}{4 y})^{2} = (\frac{3}{4 y})^{2}

= (\frac{3}{4 y})^{2}

使用指数法则:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 3 ) ^{2}}{( 4 y ) ^{2}}

使用指数法则:

(a \cdot b)^{n} = a^{n} b^{n}

(4 y)^{2} = 4^{2} y^{2}

= \frac{( 3 ) ^{2}}{4 ^{2} y ^{2}}

(3)^{2} : 3

使用根式运算法则:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

使用指数法则:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

约分:

2

= 1

= 3

= \frac{3}{4 ^{2} y ^{2}}

4^{2} = 16

= \frac{3}{16 y ^{2}}

\frac{3}{16 y ^{2}} - y^{2} = \frac{1}{2}

找到

16 y^{2}, 2

的最小公倍数:

16 y^{2}

16 y^{2}, 2

最小公倍数 (LCM)

16, 2

的最小公倍数:

16

16, 2

最小公倍数 (LCM)

16

质因数分解:

2 \cdot 2 \cdot 2 \cdot 2

16

16

除以

216 = 8 \cdot 2

= 2 \cdot 8

8

除以

28 = 4 \cdot 2

= 2 \cdot 2 \cdot 4

4

除以

24 = 2 \cdot 2

= 2 \cdot 2 \cdot 2 \cdot 2

2

质因数分解:

2

2

2

是质数，因此无法因数分解

= 2

将每个因子乘以它在

16

或

2

中出现的最多次数

= 2 \cdot 2 \cdot 2 \cdot 2

数字相乘:

2 \cdot 2 \cdot 2 \cdot 2 = 16

= 16

计算出由出现在

16 y^{2}

或

2

中的因子组成的表达式

= 16 y^{2}

乘以最小公倍数=

16 y^{2}

\frac{3}{16 y ^{2}} \cdot 16 y^{2} - y^{2} \cdot 16 y^{2} = \frac{1}{2} \cdot 16 y^{2}

化简

\frac{3}{16 y ^{2}} \cdot 16 y^{2} - y^{2} \cdot 16 y^{2} = \frac{1}{2} \cdot 16 y^{2}

化简

\frac{3}{16 y ^{2}} \cdot 16 y^{2} : 3

\frac{3}{16 y ^{2}} \cdot 16 y^{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 \cdot 16 y ^{2}}{16 y ^{2}}

约分:

16

= \frac{3 y ^{2}}{y ^{2}}

约分:

y^{2}

= 3

化简

- y^{2} \cdot 16 y^{2} : - 16 y^{4}

- y^{2} \cdot 16 y^{2}

使用指数法则:

a^{b} \cdot a^{c} = a^{b + c}

y^{2} y^{2} = y^{2 + 2}

= - 16 y^{2 + 2}

数字相加:

2 + 2 = 4

= - 16 y^{4}

化简

\frac{1}{2} \cdot 16 y^{2} : 8 y^{2}

\frac{1}{2} \cdot 16 y^{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 16}{2} y^{2}

\frac{1 \cdot 16}{2} = 8

\frac{1 \cdot 16}{2}

数字相乘:

1 \cdot 16 = 16

= \frac{16}{2}

数字相除:

\frac{16}{2} = 8

= 8

= 8 y^{2}

3 - 16 y^{4} = 8 y^{2}

3 - 16 y^{4} = 8 y^{2}

3 - 16 y^{4} = 8 y^{2}

解

3 - 16 y^{4} = 8 y^{2} : y = \frac{1}{2}, y = - \frac{1}{2}

3 - 16 y^{4} = 8 y^{2}

将

8 y^{2}

para o lado esquerdo

3 - 16 y^{4} = 8 y^{2}

两边减去

8 y^{2}

3 - 16 y^{4} - 8 y^{2} = 8 y^{2} - 8 y^{2}

化简

3 - 16 y^{4} - 8 y^{2} = 0

3 - 16 y^{4} - 8 y^{2} = 0

改写成标准形式

a_{n} x^{n} + \dots + a_{1} x + a = 0

- 16 y^{4} - 8 y^{2} + 3 = 0

用

u = y^{2}

和

u^{2} = y^{4}

改写方程式

- 16 u^{2} - 8 u + 3 = 0

解

- 16 u^{2} - 8 u + 3 = 0 : u = - \frac{3}{4}, u = \frac{1}{4}

- 16 u^{2} - 8 u + 3 = 0

使用求根公式求解

- 16 u^{2} - 8 u + 3 = 0

二次方程求根公式:

若

a = - 16, b = - 8, c = 3

u_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 16 ) \cdot 3}{2 ( - 16 )}

u_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 16 ) \cdot 3}{2 ( - 16 )}

(- 8)^{2} - 4 (- 16) \cdot 3 = 16

(- 8)^{2} - 4 (- 16) \cdot 3

使用法则

- (- a) = a

= (- 8)^{2} + 4 \cdot 16 \cdot 3

使用指数法则:

(- a)^{n} = a^{n},

若

n

是偶数

(- 8)^{2} = 8^{2}

= 8^{2} + 4 \cdot 16 \cdot 3

数字相乘:

4 \cdot 16 \cdot 3 = 192

= 8^{2} + 192

8^{2} = 64

= 64 + 192

数字相加:

64 + 192 = 256

= 256

因式分解数字:

256 = 1 6^{2}

= 1 6^{2}

使用根式运算法则:

n a^{n} = a

1 6^{2} = 16

= 16

u_{1, 2} = \frac{- ( - 8 ) \pm 16}{2 ( - 16 )}

将解分隔开

u_{1} = \frac{- ( - 8 ) + 16}{2 ( - 16 )}, u_{2} = \frac{- ( - 8 ) - 16}{2 ( - 16 )}

u = \frac{- ( - 8 ) + 16}{2 ( - 16 )} : - \frac{3}{4}

\frac{- ( - 8 ) + 16}{2 ( - 16 )}

去除括号:

(- a) = - a, - (- a) = a

= \frac{8 + 16}{- 2 \cdot 16}

数字相加:

8 + 16 = 24

= \frac{24}{- 2 \cdot 16}

数字相乘:

2 \cdot 16 = 32

= \frac{24}{- 32}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{24}{32}

约分:

8

= - \frac{3}{4}

u = \frac{- ( - 8 ) - 16}{2 ( - 16 )} : \frac{1}{4}

\frac{- ( - 8 ) - 16}{2 ( - 16 )}

去除括号:

(- a) = - a, - (- a) = a

= \frac{8 - 16}{- 2 \cdot 16}

数字相减:

8 - 16 = - 8

= \frac{- 8}{- 2 \cdot 16}

数字相乘:

2 \cdot 16 = 32

= \frac{- 8}{- 32}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{8}{32}

约分:

8

= \frac{1}{4}

二次方程组的解是:

u = - \frac{3}{4}, u = \frac{1}{4}

u = - \frac{3}{4}, u = \frac{1}{4}

代回

u = y^{2}

，求解

y

解

y^{2} = - \frac{3}{4} : y \in R

无解

y^{2} = - \frac{3}{4}

x^{2}

在

x

内不能为负

\in R

y \in R 无解

解

y^{2} = \frac{1}{4} : y = \frac{1}{2}, y = - \frac{1}{2}

y^{2} = \frac{1}{4}

对于

x^{2} = f (a)

解为

x = f (a), - f (a)

y = \frac{1}{4}, y = - \frac{1}{4}

\frac{1}{4} = \frac{1}{2}

\frac{1}{4}

使用根式运算法则:

\frac{a}{b} = \frac{a}{b}, a \geq 0, b \geq 0

= \frac{1}{4}

使用根式运算法则:

1 = 1

1 = 1

= \frac{1}{4}

4 = 2

4

因式分解数字:

4 = 2^{2}

= 2^{2}

使用根式运算法则:

a^{2} = a, a \geq 0

2^{2} = 2

= 2

= \frac{1}{2}

- \frac{1}{4} = - \frac{1}{2}

- \frac{1}{4}

使用根式运算法则:

\frac{a}{b} = \frac{a}{b}, a \geq 0, b \geq 0

= - \frac{1}{4}

使用根式运算法则:

1 = 1

1 = 1

= - \frac{1}{4}

4 = 2

4

因式分解数字:

4 = 2^{2}

= 2^{2}

使用根式运算法则:

a^{2} = a, a \geq 0

2^{2} = 2

= 2

= - \frac{1}{2}

y = \frac{1}{2}, y = - \frac{1}{2}

解为

y = \frac{1}{2}, y = - \frac{1}{2}

y = \frac{1}{2}, y = - \frac{1}{2}

验证解

找到无定义的点（奇点）:

y = 0

取

(- \frac{3}{4 y})^{2} - y^{2}

的分母，令其等于零

解

4 y = 0 : y = 0

4 y = 0

两边除以

4

4 y = 0

两边除以

4

\frac{4 y}{4} = \frac{0}{4}

化简

y = 0

y = 0

以下点无定义

y = 0

将不在定义域的点与解相综合:

y = \frac{1}{2}, y = - \frac{1}{2}

将解

y = \frac{1}{2}, y = - \frac{1}{2}

代入

2 x y = - \frac{3}{2}

对于

2 x y = - \frac{3}{2}

，用

\frac{1}{2}

替代

y : x = - \frac{3}{2}

对于

2 x y = - \frac{3}{2}

，用

\frac{1}{2}

替代

y

2 x \frac{1}{2} = - \frac{3}{2}

解

2 x \frac{1}{2} = - \frac{3}{2} : x = - \frac{3}{2}

2 x \frac{1}{2} = - \frac{3}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

\frac{1 \cdot 2}{2} x = - \frac{3}{2}

约分:

2

x \cdot 1 = - \frac{3}{2}

乘以:

x \cdot 1 = x

x = - \frac{3}{2}

对于

2 x y = - \frac{3}{2}

，用

- \frac{1}{2}

替代

y : x = \frac{3}{2}

对于

2 x y = - \frac{3}{2}

，用

- \frac{1}{2}

替代

y

2 x (- \frac{1}{2}) = - \frac{3}{2}

解

2 x (- \frac{1}{2}) = - \frac{3}{2} : x = \frac{3}{2}

2 x (- \frac{1}{2}) = - \frac{3}{2}

两边除以

2 (- \frac{1}{2})

2 x (- \frac{1}{2}) = - \frac{3}{2}

两边除以

2 (- \frac{1}{2})

\frac{2 x ( - \frac{1}{2} )}{2 ( - \frac{1}{2} )} = \frac{- \frac{3}{2}}{2 ( - \frac{1}{2} )}

化简

\frac{2 x ( - \frac{1}{2} )}{2 ( - \frac{1}{2} )} = \frac{- \frac{3}{2}}{2 ( - \frac{1}{2} )}

化简

\frac{2 x ( - \frac{1}{2} )}{2 ( - \frac{1}{2} )} : x

\frac{2 x ( - \frac{1}{2} )}{2 ( - \frac{1}{2} )}

去除括号:

(- a) = - a

= \frac{- 2 x \frac{1}{2}}{- 2 \cdot \frac{1}{2}}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{2 x \frac{1}{2}}{2 \cdot \frac{1}{2}}

乘

2 x \frac{1}{2} : x

2 x \frac{1}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2 x}{2}

约分:

2

= 1 \cdot x

乘以:

1 \cdot x = x

= x

= \frac{x}{2 \cdot \frac{1}{2}}

乘

2 \cdot \frac{1}{2} : 1

2 \cdot \frac{1}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

约分:

2

= 1

= \frac{x}{1}

使用法则

\frac{a}{1} = a

= x

化简

\frac{- \frac{3}{2}}{2 ( - \frac{1}{2} )} : \frac{3}{2}

\frac{- \frac{3}{2}}{2 ( - \frac{1}{2} )}

去除括号:

(- a) = - a

= \frac{- \frac{3}{2}}{- 2 \cdot \frac{1}{2}}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{\frac{3}{2}}{2 \cdot \frac{1}{2}}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3}{2 \cdot 2 \cdot \frac{1}{2}}

数字相乘:

2 \cdot 2 = 4

= \frac{3}{4 \cdot \frac{1}{2}}

乘

4 \cdot \frac{1}{2} : 2

4 \cdot \frac{1}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 4}{2}

数字相乘:

1 \cdot 4 = 4

= \frac{4}{2}

数字相除:

\frac{4}{2} = 2

= 2

= \frac{3}{2}

x = \frac{3}{2}

x = \frac{3}{2}

x = \frac{3}{2}

将解代入原方程进行验证

将它们代入

x^{2} - y^{2} = \frac{1}{2}

检验解是否符合

去除与方程不符的解。

检验

x = \frac{3}{2}, y = - \frac{1}{2}

的解:

真

x^{2} - y^{2} = \frac{1}{2}

代入

x = \frac{3}{2}, y = - \frac{1}{2}

(\frac{3}{2})^{2} - (- \frac{1}{2})^{2} = \frac{1}{2}

整理后得

\frac{1}{2} = \frac{1}{2}

真

检验

x = - \frac{3}{2}, y = \frac{1}{2}

的解:

真

x^{2} - y^{2} = \frac{1}{2}

代入

x = - \frac{3}{2}, y = \frac{1}{2}

(- \frac{3}{2})^{2} - (\frac{1}{2})^{2} = \frac{1}{2}

整理后得

\frac{1}{2} = \frac{1}{2}

真

将它们代入

2 x y = - \frac{3}{2}

检验解是否符合

去除与方程不符的解。

检验

x = \frac{3}{2}, y = - \frac{1}{2}

的解:

真

2 x y = - \frac{3}{2}

代入

x = \frac{3}{2}, y = - \frac{1}{2}

2 \cdot \frac{3}{2} (- \frac{1}{2}) = - \frac{3}{2}

整理后得

- \frac{3}{2} = - \frac{3}{2}

真

检验

x = - \frac{3}{2}, y = \frac{1}{2}

的解:

真

2 x y = - \frac{3}{2}

代入

x = - \frac{3}{2}, y = \frac{1}{2}

2 (- \frac{3}{2}) \frac{1}{2} = - \frac{3}{2}

整理后得

- \frac{3}{2} = - \frac{3}{2}

真

因而，

x^{2} - y^{2} = \frac{1}{2}, 2 x y = - \frac{3}{2}

最后的解是

(x = - \frac{3}{2}, x = \frac{3}{2}, y = \frac{1}{2} y = - \frac{1}{2})

u = x + y i

代回

u = - \frac{3}{2} + \frac{1}{2} i, u = \frac{3}{2} - \frac{1}{2} i

解为

u = \frac{3}{2} + \frac{1}{2} i, u = - \frac{3}{2} - \frac{1}{2} i, u = - \frac{3}{2} + \frac{1}{2} i, u = \frac{3}{2} - \frac{1}{2} i

u = \frac{3}{2} + \frac{1}{2} i, u = - \frac{3}{2} - \frac{1}{2} i, u = - \frac{3}{2} + \frac{1}{2} i, u = \frac{3}{2} - \frac{1}{2} i

u = sec (a)

代回

sec (a) = \frac{3}{2} + \frac{1}{2} i, sec (a) = - \frac{3}{2} - \frac{1}{2} i, sec (a) = - \frac{3}{2} + \frac{1}{2} i, sec (a) = \frac{3}{2} - \frac{1}{2} i

sec (a) = \frac{3}{2} + \frac{1}{2} i, sec (a) = - \frac{3}{2} - \frac{1}{2} i, sec (a) = - \frac{3}{2} + \frac{1}{2} i, sec (a) = \frac{3}{2} - \frac{1}{2} i

sec (a) = \frac{3}{2} + \frac{1}{2} i :

无解

sec (a) = \frac{3}{2} + \frac{1}{2} i

无解

sec (a) = - \frac{3}{2} - \frac{1}{2} i :

无解

sec (a) = - \frac{3}{2} - \frac{1}{2} i

无解

sec (a) = - \frac{3}{2} + \frac{1}{2} i :

无解

sec (a) = - \frac{3}{2} + \frac{1}{2} i

无解

sec (a) = \frac{3}{2} - \frac{1}{2} i :

无解

sec (a) = \frac{3}{2} - \frac{1}{2} i

无解

合并所有解

a \in R 无解

作图

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