erweitern (3x+1)((x+2))/((x-1=0))

Lösung

erweitern

(3 x + 1) \frac{( x + 2 )}{( x - 1 = 0 )}

3 \cdot \frac{( x + 2 )}{( x - 1 \cdot 0 = )} x + 1 \cdot \frac{( x + 2 )}{( x - 1 \cdot 0 = )}

Schritte zur Lösung

(3 x + 1) \frac{( x + 2 )}{( x - 1 = 0 )}

= \frac{( x + 2 )}{( x - 1 \cdot 0 = )} (3 x + 1)

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = \frac{( x + 2 )}{( x - 1 = 0 )}, b = 3 x, c = 1

= \frac{( x + 2 )}{( x - 1 = 0 )} \cdot 3 x + \frac{( x + 2 )}{( x - 1 = 0 )} \cdot 1

= 3 \cdot \frac{( x + 2 )}{( x - 1 \cdot 0 = )} x + 1 \cdot \frac{( x + 2 )}{( x - 1 \cdot 0 = )}

e x p an d \frac{4 + x}{3 1 - 2 x}

e x p an d (x + y) e^{- x^{2} - y^{2}}

e x p an d (4 z + x^{2} z) d z + (1 + z^{2}) x d x - (y z^{2} + y) (4 + x^{2}) d y

e x p an d \frac{d}{d x} (y (x + y + 1)) + \frac{d}{d y} (x + 2 y)

e x p an d (x^{3} + y^{3}) d x + (3 x y^{2} + 2) d y