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受欢迎的代数 >

solvefor x,tx^2-12x+9=0

解答

求解

x, t x^{2} - 12 x + 9 = 0

解答

x = \frac{3 ( - t + 4 + 2 )}{t}, x = \frac{3 ( - - t + 4 + 2 )}{t}; t \neq = 0

求解步骤

t x^{2} - 12 x + 9 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 t \cdot 9}{2 t}

化简

(- 12)^{2} - 4 t \cdot 9 : 6 4 - t

x_{1, 2} = \frac{- ( - 12 ) \pm 6 4 - t}{2 t}; t \neq = 0

将解分隔开

x_{1} = \frac{- ( - 12 ) + 6 4 - t}{2 t}, x_{2} = \frac{- ( - 12 ) - 6 4 - t}{2 t}

x = \frac{- ( - 12 ) + 6 4 - t}{2 t} : \frac{3 ( - t + 4 + 2 )}{t}

x = \frac{- ( - 12 ) - 6 4 - t}{2 t} : \frac{3 ( - - t + 4 + 2 )}{t}

二次方程组的解是:

x = \frac{3 ( - t + 4 + 2 )}{t}, x = \frac{3 ( - - t + 4 + 2 )}{t}; t \neq = 0

作图

流行的例子

(2 x + 1)^{2} = 1

4 (5 x - 2)^{2} - 9 = 4

2 x^{2} - 20 x = 14

v^{2} = 12 v - 25

5t^2-21t+11=-4t

5 t^{2} - 21 t + 11 = - 4 t