solvefor x,ax^2+bx=0

解

x, a x^{2} + b x = 0

x = 0, x = - \frac{b}{a}; a \neq = 0

解答ステップ

a x^{2} + b x = 0

解くとthe二次式

x_{1, 2} = \frac{- b \pm b ^{2} - 4 a \cdot 0}{2 a}

簡素化

b^{2} - 4 a \cdot 0 : b

x_{1, 2} = \frac{- b \pm b}{2 a}; a \neq = 0

解を分離する

x_{1} = \frac{- b + b}{2 a}, x_{2} = \frac{- b - b}{2 a}

x = \frac{- b + b}{2 a} : 0

x = \frac{- b - b}{2 a} : - \frac{b}{a}

二次equationの解:

x = 0, x = - \frac{b}{a}; a \neq = 0