vereinfachen (x^{-1}*y^3)^{1/2}

Lösung

vereinfachen

(x^{- 1} \cdot y^{3})^{\frac{1}{2}}

(\frac{y ^{3}}{x})^{\frac{1}{2}}

Schritte zur Lösung

(x^{- 1} y^{3})^{\frac{1}{2}}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(x^{- 1} y^{3})^{\frac{1}{2}} = (x^{- 1})^{\frac{1}{2}} (y^{3})^{\frac{1}{2}}

= (x^{- 1})^{\frac{1}{2}} (y^{3})^{\frac{1}{2}}

Vereinfache

(x^{- 1})^{\frac{1}{2}} : \frac{1}{x ^{\frac{1}{2}}}

= \frac{1}{x ^{\frac{1}{2}}} (y^{3})^{\frac{1}{2}}

Vereinfache

(y^{3})^{\frac{1}{2}} : y^{\frac{3}{2}}

= \frac{1}{x ^{\frac{1}{2}}} y^{\frac{3}{2}}

Vereinfache

\frac{1}{x ^{\frac{1}{2}}} y^{\frac{3}{2}} : (\frac{y ^{3}}{x})^{\frac{1}{2}}

= (\frac{y ^{3}}{x})^{\frac{1}{2}}

s im pl i f y \frac{2 ^{3} ( x ^{2} ) ^{3}}{2 ^{2}}

e x p an d (x - y + 2 z)^{3}

e x p an d (3 x^{2} + 4 x y + 5 y^{2}) (7 x^{2} + 9 y^{2})

f a c t or a^{4} - 2 a^{3} \cdot b + a^{2} \cdot b^{2} - b^{4}

s im pl i f y 5^{2} n - 3 - 5^{2} n - 1 + 2 5^{n} - 1