vereinfachen ((1)((a-b)^2-c^2))/((a^2-(b+c)^2))

Lösung

vereinfachen

\frac{( 1 ) ( ( a - b ) ^{2} - c ^{2} )}{( a ^{2} - ( b + c ) ^{2} )}

\frac{a - b + c}{a + b + c}

Schritte zur Lösung

\frac{( 1 ) ( ( a - b ) ^{2} - c ^{2} )}{a ^{2} - ( b + c ) ^{2}}

Apply rule:

(a) = a

(1) = 1

= \frac{1 \cdot ( ( a - b ) ^{2} - c ^{2} )}{a ^{2} - ( b + c ) ^{2}}

Apply rule:

1 \cdot a = a

1 \cdot ((a - b)^{2} - c^{2}) = ((a - b)^{2} - c^{2})

= \frac{( a - b ) ^{2} - c ^{2}}{a ^{2} - ( b + c ) ^{2}}

Faktorisiere

(a - b)^{2} - c^{2} : (a - b + c) (a - b - c)

= \frac{( a - b + c ) ( a - b - c )}{a ^{2} - ( b + c ) ^{2}}

Faktorisiere

a^{2} - (b + c)^{2} : (a + b + c) (a - b - c)

= \frac{( a - b + c ) ( a - b - c )}{( a + b + c ) ( a - b - c )}

Streiche die gemeinsamen Faktoren:

a - b - c

= \frac{a - b + c}{a + b + c}

f a c t or 8 + 36 x + 54 x^{2} + 27 x^{3}

f a c t or x^{4} y^{2} - 10 x^{2} y^{4} + 9 y^{6}

s im pl i f y (i - a)^{- 1}

s im pl i f y 2 e^{z + 2}

s im pl i f y \frac{6 n ^{- 3} y}{2 n ^{- 1} y ^{- 3}}