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人気のある代数 >

x^2+2(m+1)x-3m(m-2)=0

解

x^{2} + 2 (m + 1) x - 3 m (m - 2) = 0

解

x = m - 2, x = - 3 m

解答ステップ

x^{2} + 2 (m + 1) x - 3 m (m - 2) = 0

拡張

x^{2} + 2 (m + 1) x - 3 m (m - 2) : x^{2} + 2 m x + 2 x - 3 m^{2} + 6 m

x^{2} + 2 m x + 2 x - 3 m^{2} + 6 m = 0

標準的な形式で書く

a x^{2} + b x + c = 0

x^{2} + (2 m + 2) x - 3 m^{2} + 6 m = 0

解くとthe二次式

x_{1, 2} = \frac{- ( 2 m + 2 ) \pm ( 2 m + 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 m ^{2} + 6 m )}{2 \cdot 1}

簡素化

(2 m + 2)^{2} - 4 \cdot 1 \cdot (- 3 m^{2} + 6 m) : 2 (2 m - 1)

x_{1, 2} = \frac{- ( 2 m + 2 ) \pm 2 ( 2 m - 1 )}{2 \cdot 1}

解を分離する

x_{1} = \frac{- ( 2 m + 2 ) + 2 ( 2 m - 1 )}{2 \cdot 1}, x_{2} = \frac{- ( 2 m + 2 ) - 2 ( 2 m - 1 )}{2 \cdot 1}

x = \frac{- ( 2 m + 2 ) + 2 ( 2 m - 1 )}{2 \cdot 1} : m - 2

x = \frac{- ( 2 m + 2 ) - 2 ( 2 m - 1 )}{2 \cdot 1} : - 3 m

二次equationの解:

x = m - 2, x = - 3 m

グラフ

人気の例

solvefor x,f=f(x^2)-2f(1)

so l v e f or x, f = f (x^{2}) - 2 f (1)

solvefor x,x^2+y^2+z^2-25=0

so l v e f or x, x^{2} + y^{2} + z^{2} - 25 = 0

- x^{2} + 10 x + 24 = 0

solvefor x,g=2x^2+x-3g(-2)

so l v e f or x, g = 2 x^{2} + x - 3 g (- 2)

x^{2} - 1 = x - 2