|x|+|(4-x^2)/x |=| 4/x |

解答

∣ x ∣ + \frac{4 - x ^{2}}{x} = \frac{4}{x}

- 2 \leq x \leq 2

求解步骤

∣ x ∣ + \frac{4 - x ^{2}}{x} = \frac{4}{x}

化简

∣ x ∣ + \frac{4 - x ^{2}}{∣ x ∣} = \frac{4}{∣ x ∣}

在两边乘以

∣ x ∣

∣ x ∣^{2} + 4 - x^{2} = 4

解

∣ x ∣^{2} + 4 - x^{2} = 4 : - 2 \leq x \leq 2

- 2 \leq x \leq 2

\frac{24}{20 + x} = \frac{24 + x}{44 + x}

so l v e f or x, f (x)^{- 1} = \frac{( 4 x - 3 )}{( x + 4 )}

so l v e f or x, \frac{15}{x} + y = 7

4 (\frac{x - 1}{x})^{2} + 8 (\frac{x + 1}{x}) - 29 = 0

x^{2} + \frac{1}{x ^{2}} = 727