25^{x-3}=(1/125)^{x+2}

Lösung

2 5^{x - 3} = (\frac{1}{125})^{x + 2}

x = 0

Schritte zur Lösung

2 5^{x - 3} = (\frac{1}{125})^{x + 2}

Wende Exponentenregel an

2 (x - 3) = - 3 (x + 2)

Löse

2 (x - 3) = - 3 (x + 2) : x = 0

x = 0

(5^{x})^{2} - 26 (5^{x}) + 25 = 0

5^{x^{2} + x} = 1

2 = e^{c}

4^{x} - 5 \cdot 2^{x} + 6 = 0

g (e^{n} - 1) = ln (e^{n} - 1 - 1)