2^{x+3}=5^{x-1}

Lösung

2^{x + 3} = 5^{x - 1}

x = \frac{ln ( 40 )}{ln ( 5 ) - ln ( 2 )}

Dezimale

x = 4.02588 \dots

Schritte zur Lösung

2^{x + 3} = 5^{x - 1}

Wende Exponentenregel an

(x + 3) ln (2) = (x - 1) ln (5)

Löse

(x + 3) ln (2) = (x - 1) ln (5) : x = \frac{ln ( 40 )}{ln ( 5 ) - ln ( 2 )}

x = \frac{ln ( 40 )}{ln ( 5 ) - ln ( 2 )}

3^{- x + 1} = 4^{x + 2}

10 e^{8 x + 3} + 2 = 8

8^{2 x + 1} = 3 4^{x - 1}

3^{x - 1} + 3^{x} + 3^{x + 1} = 117

2^{2} n = 4^{n}