What are the solutions to the equation 3(x-2)(x^2+9)=0 ?

The solutions to the equation 3(x-2)(x^2+9)=0 are x=2,x=3i,x=-3i

Find the zeros of 3(x-2)(x^2+9)=0

The zeros of 3(x-2)(x^2+9)=0 are x=2,x=3i,x=-3i

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3 (x - 2) (x^{2} + 9) = 0

x = 2, x = 3 i, x = - 3 i

Solution steps

3 (x - 2) (x^{2} + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} + 9 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + 9 = 0 : x = 3 i, x = - 3 i

The solutions are

x = 2, x = 3 i, x = - 3 i

9 x^{3} - \frac{4}{5} x^{2} + x - 3 = 68

- 3 x^{3} x = 2

x^{3} - 6 x^{2} + 13 x - 10 = 0

2 y^{3} - 17 y^{2} - 9 y = 0

x^{400} = 9^{1000}

What are the solutions to the equation 3(x-2)(x^2+9)=0 ?
The solutions to the equation 3(x-2)(x^2+9)=0 are x=2,x=3i,x=-3i
Find the zeros of 3(x-2)(x^2+9)=0
The zeros of 3(x-2)(x^2+9)=0 are x=2,x=3i,x=-3i