solvefor x,ln(1-y^2-x)=0

解答

求解

x, ln (1 - y^{2} - x) = 0

x = - y^{2}

求解步骤

ln (1 - y^{2} - x) = 0

使用对数运算法则

1 - y^{2} - x = 1

解

1 - y^{2} - x = 1 : x = - y^{2}

x = - y^{2}

17 ln (x) = 11

lo g_{5} (x + 7) = lo g_{5} (2 x + 3)

lo g_{3} (x + 3) - lo g_{3} (x - 5) = 2

x = e^{\frac{l n ( x )}{x}}

lo g_{x} (x) = 3