derivative of (6x/(2x^{1/3)})

Lösung

\frac{d}{d x} (\frac{6 x}{2 x ^{\frac{1}{3}}})

\frac{2}{x ^{\frac{1}{3}}}

Schritte zur Lösung

\frac{d}{d x} (\frac{6 x}{2 x ^{\frac{1}{3}}})

Vereinfache

\frac{6 x}{2 x ^{\frac{1}{3}}} : 3 x^{\frac{2}{3}}

= \frac{d}{d x} (3 x^{\frac{2}{3}})

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{\frac{2}{3}})

Wende die Potenzregel an:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 \cdot \frac{2}{3} x^{\frac{2}{3} - 1}

Vereinfache

3 \cdot \frac{2}{3} x^{\frac{2}{3} - 1} : \frac{2}{x ^{\frac{1}{3}}}

= \frac{2}{x ^{\frac{1}{3}}}

y^{^{''}} + y = sin (x)

\int_{0}^{1} 40 \frac{1}{x ^{p}} d x

\int (x + 2) 3 x^{2} + 4 x + 2 d x

\int \frac{( ( ( x ) + 1 ) \cdot ( x - 1 ) )}{( x )} d x

t an g e n t f (x) = x^{2} + 2, (- 2, 6)