integral of-18x^{-19}

解答

\int - 18 x^{- 19} d x

\frac{1}{x ^{18}} + C

求解步骤

\int - 18 x^{- 19} d x

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 18 \cdot \int x^{- 19} d x

使用幂法则

= - 18 (- \frac{1}{18 x ^{18}})

化简

- 18 (- \frac{1}{18 x ^{18}}) : \frac{1}{x ^{18}}

= \frac{1}{x ^{18}}

解答补常数

= \frac{1}{x ^{18}} + C

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