integral of (60)/(2x+5)-4

Lösung

\int \frac{60}{2 x + 5} - 4 d x

30 ln ∣ 2 x + 5 ∣ - 4 x + C

Schritte zur Lösung

\int \frac{60}{2 x + 5} - 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{60}{2 x + 5} d x - \int 4 d x

\int \frac{60}{2 x + 5} d x = 30 ln ∣ 2 x + 5 ∣

\int 4 d x = 4 x

= 30 ln ∣ 2 x + 5 ∣ - 4 x

Füge eine Konstante zur Lösung hinzu

= 30 ln ∣ 2 x + 5 ∣ - 4 x + C

\int_{1}^{8} x^{- \frac{2}{3}} d x

\int \frac{36 - x ^{2}}{x ^{2}} d x

d er i v a t i v e f (x) = \frac{x ^{2} 3 x}{6}

\int a e^{a x} (2 + a x) d x

\frac{\partial}{\partial x} (arctan (x \cdot t))