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人気のある三角関数 >

tan^2(x)= 1/3 ,0<= x<= 720

解

tan^{2} (x) = \frac{1}{3}, 0^{\circ} \leq x \leq 72 0^{\circ}

解

x = 3 0^{\circ}, x = 21 0^{\circ}, x = 39 0^{\circ}, x = 57 0^{\circ}, x = 15 0^{\circ}, x = 33 0^{\circ}, x = 51 0^{\circ}, x = 69 0^{\circ}

+1

ラジアン

x = \frac{π}{6}, x = \frac{7 π}{6}, x = \frac{13 π}{6}, x = \frac{19 π}{6}, x = \frac{5 π}{6}, x = \frac{11 π}{6}, x = \frac{17 π}{6}, x = \frac{23 π}{6}

解答ステップ

tan^{2} (x) = \frac{1}{3}, 0^{\circ} \leq x \leq 72 0^{\circ}

置換で解く

tan^{2} (x) = \frac{1}{3}

仮定:

tan (x) = u

u^{2} = \frac{1}{3}

u^{2} = \frac{1}{3} : u = \frac{1}{3}, u = - \frac{1}{3}

u^{2} = \frac{1}{3}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

u = \frac{1}{3}, u = - \frac{1}{3}

代用を戻す

u = tan (x)

tan (x) = \frac{1}{3}, tan (x) = - \frac{1}{3}

tan (x) = \frac{1}{3}, tan (x) = - \frac{1}{3}

tan (x) = \frac{1}{3}, 0 \leq x \leq 72 0^{\circ} : x = 3 0^{\circ}, x = 21 0^{\circ}, x = 39 0^{\circ}, x = 57 0^{\circ}

tan (x) = \frac{1}{3}, 0 \leq x \leq 72 0^{\circ}

三角関数の逆数プロパティを適用する

tan (x) = \frac{1}{3}

以下の一般解

tan (x) = \frac{1}{3}

tan (x) = a \Rightarrow x = arctan (a) + 18 0^{\circ} n

x = arctan (\frac{1}{3}) + 18 0^{\circ} n

x = arctan (\frac{1}{3}) + 18 0^{\circ} n

範囲の解答

0 \leq x \leq 72 0^{\circ}

x = 3 0^{\circ}, x = 21 0^{\circ}, x = 39 0^{\circ}, x = 57 0^{\circ}

tan (x) = - \frac{1}{3}, 0 \leq x \leq 72 0^{\circ} : x = 15 0^{\circ}, x = 33 0^{\circ}, x = 51 0^{\circ}, x = 69 0^{\circ}

tan (x) = - \frac{1}{3}, 0 \leq x \leq 72 0^{\circ}

三角関数の逆数プロパティを適用する

tan (x) = - \frac{1}{3}

以下の一般解

tan (x) = - \frac{1}{3}

tan (x) = - a \Rightarrow x = arctan (- a) + 18 0^{\circ} n

x = arctan (- \frac{1}{3}) + 18 0^{\circ} n

x = arctan (- \frac{1}{3}) + 18 0^{\circ} n

範囲の解答

0 \leq x \leq 72 0^{\circ}

x = 15 0^{\circ}, x = 33 0^{\circ}, x = 51 0^{\circ}, x = 69 0^{\circ}

すべての解を組み合わせる

x = 3 0^{\circ}, x = 21 0^{\circ}, x = 39 0^{\circ}, x = 57 0^{\circ}, x = 15 0^{\circ}, x = 33 0^{\circ}, x = 51 0^{\circ}, x = 69 0^{\circ}

グラフ

人気の例

tan(x)-sec(x)=3,0<= x<2pi

tan (x) - sec (x) = 3, 0 \leq x < 2 π

sin^2(θ)+2cos^2(θ)=4

sin^{2} (θ) + 2 cos^{2} (θ) = 4

8-12sin^2(x)=4cos^2(x)

8 - 12 sin^{2} (x) = 4 cos^{2} (x)

3 (2 + cos (x)) = 5

tan(x)= 5/(8.66)

tan (x) = \frac{5}{8.66}