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受欢迎的三角函数 >

solvefor x,y-1=-4+3sin(4x-pi/4)

解答

求解

x, y - 1 = - 4 + 3 sin (4 x - \frac{π}{4})

解答

x = \frac{arcsin ( \frac{y + 3}{3} )}{4} + \frac{πn}{2} + \frac{π}{16}, x = \frac{π}{4} + \frac{π}{16} + \frac{πn}{2} + \frac{arcsin ( - \frac{y + 3}{3} )}{4}

求解步骤

y - 1 = - 4 + 3 sin (4 x - \frac{π}{4})

交换两边

- 4 + 3 sin (4 x - \frac{π}{4}) = y - 1

将

4

到右边

- 4 + 3 sin (4 x - \frac{π}{4}) = y - 1

两边加上

4

- 4 + 3 sin (4 x - \frac{π}{4}) + 4 = y - 1 + 4

化简

3 sin (4 x - \frac{π}{4}) = y + 3

3 sin (4 x - \frac{π}{4}) = y + 3

两边除以

3

3 sin (4 x - \frac{π}{4}) = y + 3

两边除以

3

\frac{3 sin ( 4 x - \frac{π}{4} )}{3} = \frac{y}{3} + \frac{3}{3}

化简

\frac{3 sin ( 4 x - \frac{π}{4} )}{3} = \frac{y}{3} + \frac{3}{3}

化简

\frac{3 sin ( 4 x - \frac{π}{4} )}{3} : sin (4 x - \frac{π}{4})

\frac{3 sin ( 4 x - \frac{π}{4} )}{3}

数字相除:

\frac{3}{3} = 1

= sin (4 x - \frac{π}{4})

化简

\frac{y}{3} + \frac{3}{3} : \frac{y + 3}{3}

\frac{y}{3} + \frac{3}{3}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{y + 3}{3}

sin (4 x - \frac{π}{4}) = \frac{y + 3}{3}

sin (4 x - \frac{π}{4}) = \frac{y + 3}{3}

sin (4 x - \frac{π}{4}) = \frac{y + 3}{3}

使用反三角函数性质

sin (4 x - \frac{π}{4}) = \frac{y + 3}{3}

sin (4 x - \frac{π}{4}) = \frac{y + 3}{3}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π + arcsin (a) + 2 πn

4 x - \frac{π}{4} = arcsin (\frac{y + 3}{3}) + 2 πn, 4 x - \frac{π}{4} = π + arcsin (- \frac{y + 3}{3}) + 2 πn

4 x - \frac{π}{4} = arcsin (\frac{y + 3}{3}) + 2 πn, 4 x - \frac{π}{4} = π + arcsin (- \frac{y + 3}{3}) + 2 πn

解

4 x - \frac{π}{4} = arcsin (\frac{y + 3}{3}) + 2 πn : x = \frac{arcsin ( \frac{y + 3}{3} )}{4} + \frac{πn}{2} + \frac{π}{16}

4 x - \frac{π}{4} = arcsin (\frac{y + 3}{3}) + 2 πn

将

\frac{π}{4}

到右边

4 x - \frac{π}{4} = arcsin (\frac{y + 3}{3}) + 2 πn

两边加上

\frac{π}{4}

4 x - \frac{π}{4} + \frac{π}{4} = arcsin (\frac{y + 3}{3}) + 2 πn + \frac{π}{4}

化简

4 x = arcsin (\frac{y + 3}{3}) + 2 πn + \frac{π}{4}

4 x = arcsin (\frac{y + 3}{3}) + 2 πn + \frac{π}{4}

两边除以

4

4 x = arcsin (\frac{y + 3}{3}) + 2 πn + \frac{π}{4}

两边除以

4

\frac{4 x}{4} = \frac{arcsin ( \frac{y + 3}{3} )}{4} + \frac{2 πn}{4} + \frac{\frac{π}{4}}{4}

化简

\frac{4 x}{4} = \frac{arcsin ( \frac{y + 3}{3} )}{4} + \frac{2 πn}{4} + \frac{\frac{π}{4}}{4}

化简

\frac{4 x}{4} : x

\frac{4 x}{4}

数字相除:

\frac{4}{4} = 1

= x

化简

\frac{arcsin ( \frac{y + 3}{3} )}{4} + \frac{2 πn}{4} + \frac{\frac{π}{4}}{4} : \frac{arcsin ( \frac{y + 3}{3} )}{4} + \frac{πn}{2} + \frac{π}{16}

\frac{arcsin ( \frac{y + 3}{3} )}{4} + \frac{2 πn}{4} + \frac{\frac{π}{4}}{4}

\frac{2 πn}{4} = \frac{πn}{2}

\frac{2 πn}{4}

约分:

2

= \frac{πn}{2}

\frac{\frac{π}{4}}{4} = \frac{π}{16}

\frac{\frac{π}{4}}{4}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{4 \cdot 4}

数字相乘:

4 \cdot 4 = 16

= \frac{π}{16}

= \frac{arcsin ( \frac{y + 3}{3} )}{4} + \frac{πn}{2} + \frac{π}{16}

x = \frac{arcsin ( \frac{y + 3}{3} )}{4} + \frac{πn}{2} + \frac{π}{16}

x = \frac{arcsin ( \frac{y + 3}{3} )}{4} + \frac{πn}{2} + \frac{π}{16}

x = \frac{arcsin ( \frac{y + 3}{3} )}{4} + \frac{πn}{2} + \frac{π}{16}

解

4 x - \frac{π}{4} = π + arcsin (- \frac{y + 3}{3}) + 2 πn : x = \frac{π}{4} + \frac{π}{16} + \frac{πn}{2} + \frac{arcsin ( - \frac{y + 3}{3} )}{4}

4 x - \frac{π}{4} = π + arcsin (- \frac{y + 3}{3}) + 2 πn

将

\frac{π}{4}

到右边

4 x - \frac{π}{4} = π + arcsin (- \frac{y + 3}{3}) + 2 πn

两边加上

\frac{π}{4}

4 x - \frac{π}{4} + \frac{π}{4} = π + arcsin (- \frac{y + 3}{3}) + 2 πn + \frac{π}{4}

化简

4 x = π + arcsin (- \frac{y + 3}{3}) + 2 πn + \frac{π}{4}

4 x = π + arcsin (- \frac{y + 3}{3}) + 2 πn + \frac{π}{4}

两边除以

4

4 x = π + arcsin (- \frac{y + 3}{3}) + 2 πn + \frac{π}{4}

两边除以

4

\frac{4 x}{4} = \frac{π}{4} + \frac{arcsin ( - \frac{y + 3}{3} )}{4} + \frac{2 πn}{4} + \frac{\frac{π}{4}}{4}

化简

\frac{4 x}{4} = \frac{π}{4} + \frac{arcsin ( - \frac{y + 3}{3} )}{4} + \frac{2 πn}{4} + \frac{\frac{π}{4}}{4}

化简

\frac{4 x}{4} : x

\frac{4 x}{4}

数字相除:

\frac{4}{4} = 1

= x

化简

\frac{π}{4} + \frac{arcsin ( - \frac{y + 3}{3} )}{4} + \frac{2 πn}{4} + \frac{\frac{π}{4}}{4} : \frac{π}{4} + \frac{π}{16} + \frac{πn}{2} + \frac{arcsin ( - \frac{y + 3}{3} )}{4}

\frac{π}{4} + \frac{arcsin ( - \frac{y + 3}{3} )}{4} + \frac{2 πn}{4} + \frac{\frac{π}{4}}{4}

对同类项分组

= \frac{π}{4} + \frac{2 πn}{4} + \frac{\frac{π}{4}}{4} + \frac{arcsin ( - \frac{y + 3}{3} )}{4}

\frac{2 πn}{4} = \frac{πn}{2}

\frac{2 πn}{4}

约分:

2

= \frac{πn}{2}

\frac{\frac{π}{4}}{4} = \frac{π}{16}

\frac{\frac{π}{4}}{4}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{4 \cdot 4}

数字相乘:

4 \cdot 4 = 16

= \frac{π}{16}

= \frac{π}{4} + \frac{πn}{2} + \frac{π}{16} + \frac{arcsin ( - \frac{y + 3}{3} )}{4}

对同类项分组

= \frac{π}{4} + \frac{π}{16} + \frac{πn}{2} + \frac{arcsin ( - \frac{y + 3}{3} )}{4}

x = \frac{π}{4} + \frac{π}{16} + \frac{πn}{2} + \frac{arcsin ( - \frac{y + 3}{3} )}{4}

x = \frac{π}{4} + \frac{π}{16} + \frac{πn}{2} + \frac{arcsin ( - \frac{y + 3}{3} )}{4}

x = \frac{π}{4} + \frac{π}{16} + \frac{πn}{2} + \frac{arcsin ( - \frac{y + 3}{3} )}{4}

x = \frac{arcsin ( \frac{y + 3}{3} )}{4} + \frac{πn}{2} + \frac{π}{16}, x = \frac{π}{4} + \frac{π}{16} + \frac{πn}{2} + \frac{arcsin ( - \frac{y + 3}{3} )}{4}

作图

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