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受欢迎的三角函数 >

sin(2v)=sin(16)

解答

sin (2 v) = sin (1 6^{\circ})

解答

v = 8^{\circ} + 18 0^{\circ} n, v = 9 0^{\circ} - 8^{\circ} + 18 0^{\circ} n

+1

弧度

v = \frac{2 π}{45} + πn, v = \frac{π}{2} - \frac{2 π}{45} + πn

求解步骤

sin (2 v) = sin (1 6^{\circ})

使用反三角函数性质

sin (2 v) = sin (1 6^{\circ})

sin (2 v) = sin (1 6^{\circ})

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

2 v = arcsin (sin (1 6^{\circ})) + 36 0^{\circ} n, 2 v = 18 0^{\circ} - arcsin (sin (1 6^{\circ})) + 36 0^{\circ} n

2 v = arcsin (sin (1 6^{\circ})) + 36 0^{\circ} n, 2 v = 18 0^{\circ} - arcsin (sin (1 6^{\circ})) + 36 0^{\circ} n

解

2 v = arcsin (sin (1 6^{\circ})) + 36 0^{\circ} n : v = 8^{\circ} + 18 0^{\circ} n

2 v = arcsin (sin (1 6^{\circ})) + 36 0^{\circ} n

两边除以

2

2 v = arcsin (sin (1 6^{\circ})) + 36 0^{\circ} n

两边除以

2

\frac{2 v}{2} = \frac{arcsin ( sin ( 1 6 ^{\circ} ) )}{2} + \frac{36 0 ^{\circ} n}{2}

化简

\frac{2 v}{2} = \frac{arcsin ( sin ( 1 6 ^{\circ} ) )}{2} + \frac{36 0 ^{\circ} n}{2}

化简

\frac{2 v}{2} : v

\frac{2 v}{2}

数字相除:

\frac{2}{2} = 1

= v

化简

\frac{arcsin ( sin ( 1 6 ^{\circ} ) )}{2} + \frac{36 0 ^{\circ} n}{2} : 8^{\circ} + 18 0^{\circ} n

\frac{arcsin ( sin ( 1 6 ^{\circ} ) )}{2} + \frac{36 0 ^{\circ} n}{2}

\frac{arcsin ( sin ( 1 6 ^{\circ} ) )}{2} = 8^{\circ}

\frac{arcsin ( sin ( 1 6 ^{\circ} ) )}{2}

arcsin (sin (1 6^{\circ})) = 1 6^{\circ}

arcsin (sin (1 6^{\circ}))

对于

- 9 0^{\circ} \leq v \leq 9 0^{\circ}, a rcs in (s in (x)) = x

- 9 0^{\circ} \leq 1 6^{\circ} \leq 9 0^{\circ}

= 1 6^{\circ}

= \frac{1 6 ^{\circ}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{72 0 ^{\circ}}{45 \cdot 2}

数字相乘:

45 \cdot 2 = 90

= 8^{\circ}

约分:

2

= 8^{\circ}

= 8^{\circ} + \frac{36 0 ^{\circ} n}{2}

\frac{36 0 ^{\circ} n}{2} = 18 0^{\circ} n

\frac{36 0 ^{\circ} n}{2}

数字相除:

\frac{2}{2} = 1

= 18 0^{\circ} n

= 8^{\circ} + 18 0^{\circ} n

v = 8^{\circ} + 18 0^{\circ} n

v = 8^{\circ} + 18 0^{\circ} n

v = 8^{\circ} + 18 0^{\circ} n

解

2 v = 18 0^{\circ} - arcsin (sin (1 6^{\circ})) + 36 0^{\circ} n : v = 9 0^{\circ} - 8^{\circ} + 18 0^{\circ} n

2 v = 18 0^{\circ} - arcsin (sin (1 6^{\circ})) + 36 0^{\circ} n

两边除以

2

2 v = 18 0^{\circ} - arcsin (sin (1 6^{\circ})) + 36 0^{\circ} n

两边除以

2

\frac{2 v}{2} = 9 0^{\circ} - \frac{arcsin ( sin ( 1 6 ^{\circ} ) )}{2} + \frac{36 0 ^{\circ} n}{2}

化简

\frac{2 v}{2} = 9 0^{\circ} - \frac{arcsin ( sin ( 1 6 ^{\circ} ) )}{2} + \frac{36 0 ^{\circ} n}{2}

化简

\frac{2 v}{2} : v

\frac{2 v}{2}

数字相除:

\frac{2}{2} = 1

= v

化简

9 0^{\circ} - \frac{arcsin ( sin ( 1 6 ^{\circ} ) )}{2} + \frac{36 0 ^{\circ} n}{2} : 9 0^{\circ} - 8^{\circ} + 18 0^{\circ} n

9 0^{\circ} - \frac{arcsin ( sin ( 1 6 ^{\circ} ) )}{2} + \frac{36 0 ^{\circ} n}{2}

\frac{arcsin ( sin ( 1 6 ^{\circ} ) )}{2} = 8^{\circ}

\frac{arcsin ( sin ( 1 6 ^{\circ} ) )}{2}

arcsin (sin (1 6^{\circ})) = 1 6^{\circ}

arcsin (sin (1 6^{\circ}))

对于

- 9 0^{\circ} \leq v \leq 9 0^{\circ}, a rcs in (s in (x)) = x

- 9 0^{\circ} \leq 1 6^{\circ} \leq 9 0^{\circ}

= 1 6^{\circ}

= \frac{1 6 ^{\circ}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{72 0 ^{\circ}}{45 \cdot 2}

数字相乘:

45 \cdot 2 = 90

= 8^{\circ}

约分:

2

= 8^{\circ}

= 9 0^{\circ} - 8^{\circ} + \frac{36 0 ^{\circ} n}{2}

\frac{36 0 ^{\circ} n}{2} = 18 0^{\circ} n

\frac{36 0 ^{\circ} n}{2}

数字相除:

\frac{2}{2} = 1

= 18 0^{\circ} n

= 9 0^{\circ} - 8^{\circ} + 18 0^{\circ} n

v = 9 0^{\circ} - 8^{\circ} + 18 0^{\circ} n

v = 9 0^{\circ} - 8^{\circ} + 18 0^{\circ} n

v = 9 0^{\circ} - 8^{\circ} + 18 0^{\circ} n

v = 8^{\circ} + 18 0^{\circ} n, v = 9 0^{\circ} - 8^{\circ} + 18 0^{\circ} n

作图

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