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受欢迎的三角函数 >

sin(10x)=sin(7x)

解答

sin (10 x) = sin (7 x)

解答

x = \frac{π}{17} + \frac{4 πn}{17}, x = \frac{3 π}{17} + \frac{4 πn}{17}, x = \frac{4 πn}{3}, x = \frac{2 π}{3} + \frac{4 πn}{3}

+1

度数

x = 10.58823 \dots^{\circ} + 42.35294 \dots^{\circ} n, x = 31.76470 \dots^{\circ} + 42.35294 \dots^{\circ} n, x = 0^{\circ} + 24 0^{\circ} n, x = 12 0^{\circ} + 24 0^{\circ} n

求解步骤

sin (10 x) = sin (7 x)

两边减去

sin (7 x)

sin (10 x) - sin (7 x) = 0

使用三角恒等式改写

sin (10 x) - sin (7 x)

使用和差化积恒等式:

sin (s) - sin (t) = 2 sin (\frac{s - t}{2}) cos (\frac{s + t}{2})

= 2 sin (\frac{10 x - 7 x}{2}) cos (\frac{10 x + 7 x}{2})

化简

2 sin (\frac{10 x - 7 x}{2}) cos (\frac{10 x + 7 x}{2}) : 2 sin (\frac{3 x}{2}) cos (\frac{17 x}{2})

2 sin (\frac{10 x - 7 x}{2}) cos (\frac{10 x + 7 x}{2})

同类项相加:

10 x - 7 x = 3 x

= 2 sin (\frac{3 x}{2}) cos (\frac{10 x + 7 x}{2})

同类项相加:

10 x + 7 x = 17 x

= 2 sin (\frac{3 x}{2}) cos (\frac{17 x}{2})

= 2 sin (\frac{3 x}{2}) cos (\frac{17 x}{2})

2 cos (\frac{17 x}{2}) sin (\frac{3 x}{2}) = 0

分别求解每个部分

cos (\frac{17 x}{2}) = 0 or sin (\frac{3 x}{2}) = 0

cos (\frac{17 x}{2}) = 0 : x = \frac{π}{17} + \frac{4 πn}{17}, x = \frac{3 π}{17} + \frac{4 πn}{17}

cos (\frac{17 x}{2}) = 0

cos (\frac{17 x}{2}) = 0

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

\frac{17 x}{2} = \frac{π}{2} + 2 πn, \frac{17 x}{2} = \frac{3 π}{2} + 2 πn

\frac{17 x}{2} = \frac{π}{2} + 2 πn, \frac{17 x}{2} = \frac{3 π}{2} + 2 πn

解

\frac{17 x}{2} = \frac{π}{2} + 2 πn : x = \frac{π}{17} + \frac{4 πn}{17}

\frac{17 x}{2} = \frac{π}{2} + 2 πn

在两边乘以

2

\frac{17 x}{2} = \frac{π}{2} + 2 πn

在两边乘以

2

\frac{2 \cdot 17 x}{2} = 2 \cdot \frac{π}{2} + 2 \cdot 2 πn

化简

\frac{2 \cdot 17 x}{2} = 2 \cdot \frac{π}{2} + 2 \cdot 2 πn

化简

\frac{2 \cdot 17 x}{2} : 17 x

\frac{2 \cdot 17 x}{2}

数字相乘:

2 \cdot 17 = 34

= \frac{34 x}{2}

数字相除:

\frac{34}{2} = 17

= 17 x

化简

2 \cdot \frac{π}{2} + 2 \cdot 2 πn : π + 4 πn

2 \cdot \frac{π}{2} + 2 \cdot 2 πn

2 \cdot \frac{π}{2} = π

2 \cdot \frac{π}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 2}{2}

约分:

2

= π

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

数字相乘:

2 \cdot 2 = 4

= 4 πn

= π + 4 πn

17 x = π + 4 πn

17 x = π + 4 πn

17 x = π + 4 πn

两边除以

17

17 x = π + 4 πn

两边除以

17

\frac{17 x}{17} = \frac{π}{17} + \frac{4 πn}{17}

化简

x = \frac{π}{17} + \frac{4 πn}{17}

x = \frac{π}{17} + \frac{4 πn}{17}

解

\frac{17 x}{2} = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{17} + \frac{4 πn}{17}

\frac{17 x}{2} = \frac{3 π}{2} + 2 πn

在两边乘以

2

\frac{17 x}{2} = \frac{3 π}{2} + 2 πn

在两边乘以

2

\frac{2 \cdot 17 x}{2} = 2 \cdot \frac{3 π}{2} + 2 \cdot 2 πn

化简

\frac{2 \cdot 17 x}{2} = 2 \cdot \frac{3 π}{2} + 2 \cdot 2 πn

化简

\frac{2 \cdot 17 x}{2} : 17 x

\frac{2 \cdot 17 x}{2}

数字相乘:

2 \cdot 17 = 34

= \frac{34 x}{2}

数字相除:

\frac{34}{2} = 17

= 17 x

化简

2 \cdot \frac{3 π}{2} + 2 \cdot 2 πn : 3 π + 4 πn

2 \cdot \frac{3 π}{2} + 2 \cdot 2 πn

2 \cdot \frac{3 π}{2} = 3 π

2 \cdot \frac{3 π}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 π 2}{2}

约分:

2

= 3 π

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

数字相乘:

2 \cdot 2 = 4

= 4 πn

= 3 π + 4 πn

17 x = 3 π + 4 πn

17 x = 3 π + 4 πn

17 x = 3 π + 4 πn

两边除以

17

17 x = 3 π + 4 πn

两边除以

17

\frac{17 x}{17} = \frac{3 π}{17} + \frac{4 πn}{17}

化简

x = \frac{3 π}{17} + \frac{4 πn}{17}

x = \frac{3 π}{17} + \frac{4 πn}{17}

x = \frac{π}{17} + \frac{4 πn}{17}, x = \frac{3 π}{17} + \frac{4 πn}{17}

sin (\frac{3 x}{2}) = 0 : x = \frac{4 πn}{3}, x = \frac{2 π}{3} + \frac{4 πn}{3}

sin (\frac{3 x}{2}) = 0

sin (\frac{3 x}{2}) = 0

的通解

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

\frac{3 x}{2} = 0 + 2 πn, \frac{3 x}{2} = π + 2 πn

\frac{3 x}{2} = 0 + 2 πn, \frac{3 x}{2} = π + 2 πn

解

\frac{3 x}{2} = 0 + 2 πn : x = \frac{4 πn}{3}

\frac{3 x}{2} = 0 + 2 πn

0 + 2 πn = 2 πn

\frac{3 x}{2} = 2 πn

在两边乘以

2

\frac{3 x}{2} = 2 πn

在两边乘以

2

\frac{2 \cdot 3 x}{2} = 2 \cdot 2 πn

化简

3 x = 4 πn

3 x = 4 πn

两边除以

3

3 x = 4 πn

两边除以

3

\frac{3 x}{3} = \frac{4 πn}{3}

化简

x = \frac{4 πn}{3}

x = \frac{4 πn}{3}

解

\frac{3 x}{2} = π + 2 πn : x = \frac{2 π}{3} + \frac{4 πn}{3}

\frac{3 x}{2} = π + 2 πn

在两边乘以

2

\frac{3 x}{2} = π + 2 πn

在两边乘以

2

\frac{2 \cdot 3 x}{2} = 2 π + 2 \cdot 2 πn

化简

3 x = 2 π + 4 πn

3 x = 2 π + 4 πn

两边除以

3

3 x = 2 π + 4 πn

两边除以

3

\frac{3 x}{3} = \frac{2 π}{3} + \frac{4 πn}{3}

化简

x = \frac{2 π}{3} + \frac{4 πn}{3}

x = \frac{2 π}{3} + \frac{4 πn}{3}

x = \frac{4 πn}{3}, x = \frac{2 π}{3} + \frac{4 πn}{3}

合并所有解

x = \frac{π}{17} + \frac{4 πn}{17}, x = \frac{3 π}{17} + \frac{4 πn}{17}, x = \frac{4 πn}{3}, x = \frac{2 π}{3} + \frac{4 πn}{3}

作图

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