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Problemas populares

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Problemas populares de Trigonometría

sqrt(3)cot(x/2)>-3	\sqrt{3}\cot(\frac{x}{2})>-3
tan(θ)>0,cos(θ)<0sin(θ)=-2/5 ,tan(θ)	\tan(θ)>0,\cos(θ)<0\sin(θ)=-\frac{2}{5},\tan(θ)
tan^2(x)>1	\tan^{2}(x)>1
sin(x)<tan(x)	\sin(x)<\tan(x)
2/pi-arctan(x)<0.001	\frac{2}{π}-\arctan(x)<0.001
cot(x)>= 0	\cot(x)\ge\:0
(0.75sin((2pix)/3))+1.25<1.8	(0.75\cdot\:\sin(\frac{2π\cdot\:x}{3}))+1.25<1.8
solvefor x, pi/2-arctan(x^4)<0.0001	solvefor\:x,\frac{π}{2}-\arctan(x^{4})<0.0001
cot(x)>= 1	\cot(x)\ge\:1
-(-1-cos(t))<0	-(-1-\cos(t))<0
(4cos(x)+3)/(3cos(x)+1)<2	\frac{4\cos(x)+3}{3\cos(x)+1}<2
sin^2(2x)<= 1/2	\sin^{2}(2x)\le\:\frac{1}{2}
(1-2cos^2(x))/(tan(x))>0	\frac{1-2\cos^{2}(x)}{\tan(x)}>0
sin(x)<=-(sqrt(2))/2 ,-pi<= x<= pi	\sin(x)\le\:-\frac{\sqrt{2}}{2},-π\le\:x\le\:π
2cos^2(x)+cos(x)>0	2\cos^{2}(x)+\cos(x)>0
tan(2x)<= sqrt(3)	\tan(2x)\le\:\sqrt{3}
(2sin(θ)cos(θ))/((3cos^2(θ)+1))>= 16/45	\frac{2\sin(θ)\cos(θ)}{(3\cos^{2}(θ)+1)}\ge\:\frac{16}{45}
cos(2t)>=-1/2	\cos(2t)\ge\:-\frac{1}{2}
-(-1-cos(t))>0	-(-1-\cos(t))>0
tan(3x-pi/6)<-1	\tan(3x-\frac{π}{6})<-1
cos(x/2)>0	\cos(\frac{x}{2})>0
1/2 >sin(x/2)	\frac{1}{2}>\sin(\frac{x}{2})
sin(x)<(-sqrt(3))/2	\sin(x)<\frac{-\sqrt{3}}{2}
0<2-sec(x^2)	0<2-\sec(x^{2})
7cos(x)>= 0	7\cos(x)\ge\:0
-0.25<= 0.5sin(2x),0<= x<= 360	-0.25\le\:0.5\sin(2x),0^{\circ\:}\le\:x\le\:360^{\circ\:}
cos(x/2)>= (sqrt(2))/2	\cos(\frac{x}{2})\ge\:\frac{\sqrt{2}}{2}
cos^2(x)>-2	\cos^{2}(x)>-2
pi/2-arctan(x)<0.1	\frac{π}{2}-\arctan(x)<0.1
2sin^2(x)-1<-cos(x)	2\sin^{2}(x)-1<-\cos(x)
-cos(x)-4sin(2x)>0	-\cos(x)-4\sin(2x)>0
(1+tan(x))/(1-tan(x))>0	\frac{1+\tan(x)}{1-\tan(x)}>0
arctan(x)>0.0001	\arctan(x)>0.0001
0.96(cos(x))^2<= 0.83	0.96(\cos(x))^{2}\le\:0.83
sin(3x)cos(3x)-1/4 >0	\sin(3x)\cos(3x)-\frac{1}{4}>0
cos(x/2)<0	\cos(\frac{x}{2})<0
sin(x)>0.1	\sin(x)>0.1
cos(-θ)<0	\cos(-θ)<0
cos(1/2 x)< 1/2	\cos(\frac{1}{2}x)<\frac{1}{2}
8sin^2(θ)-17sin(θ)<2pi,0<= θ<2pi	8\sin^{2}(θ)-17\sin(θ)<2π,0\le\:θ<2π
1+cos(x)>0	1+\cos(x)>0
cos(2x)<-(sqrt(2))/2 ,0<= x<= 2pi	\cos(2x)<-\frac{\sqrt{2}}{2},0\le\:x\le\:2π
sin^2(x)< 3/4 ,-pi<= x<= pi	\sin^{2}(x)<\frac{3}{4},-π\le\:x\le\:π
cos^2(x)-sin^2(x)-cos(x)<= 0	\cos^{2}(x)-\sin^{2}(x)-\cos(x)\le\:0
sin(x/6)>=-(sqrt(2))/2	\sin(\frac{x}{6})\ge\:-\frac{\sqrt{2}}{2}
sin(x)>= 1/3	\sin(x)\ge\:\frac{1}{3}
sin(x)-(sqrt(2))/2 >0	\sin(x)-\frac{\sqrt{2}}{2}>0
sin(-x)> 1/2	\sin(-x)>\frac{1}{2}
sin(x+pi/5)> 1/2	\sin(x+\frac{π}{5})>\frac{1}{2}
cos(x/2)<= 0	\cos(\frac{x}{2})\le\:0
1-2cos^2(1/2 x)>0	1-2\cos^{2}(\frac{1}{2}x)>0
sqrt(3)cos(4x)+sin(4x)>sqrt(2)	\sqrt{3}\cos(4x)+\sin(4x)>\sqrt{2}
sin(5x)>5,0<= x<= 2pi	\sin(5x)>5,0\le\:x\le\:2π
sin(2x)>6cos(x)	\sin(2x)>6\cos(x)
-cos(x)<=-sin(2x)	-\cos(x)\le\:-\sin(2x)
cos(y)>-1	\cos(y)>-1
2cos(x)+cos^2(x)>0	2\cos(x)+\cos^{2}(x)>0
tan(x)>-2/3	\tan(x)>-\frac{2}{3}
sin(x)-cos(x)>= 1	\sin(x)-\cos(x)\ge\:1
pi/4-arccos(x)>0	\frac{π}{4}-\arccos(x)>0
tan(θ)>0,csc(θ)>0	\tan(θ)>0,\csc(θ)>0
3cos(t)>= 0	3\cos(t)\ge\:0
sin(x)> 1/(sqrt(3))	\sin(x)>\frac{1}{\sqrt{3}}
cos(x)-(sqrt(2))/2 <= 0	\cos(x)-\frac{\sqrt{2}}{2}\le\:0
4*sin^2(X)-2<0	4\cdot\:\sin^{2}(X)-2<0
6cos(2x)<0	6\cos(2x)<0
-(sqrt(3))/2 sin(x)-1/2 cos(x)<= 0	-\frac{\sqrt{3}}{2}\sin(x)-\frac{1}{2}\cos(x)\le\:0
3/2 cos(x)-2>= cos(x)-7/4	\frac{3}{2}\cos(x)-2\ge\:\cos(x)-\frac{7}{4}
sin(x)< 2/pi	\sin(x)<\frac{2}{π}
2cos(x)<= 1	2\cos(x)\le\:1
tan^2(x)>5,-pi<= x<= pi	\tan^{2}(x)>5,-π\le\:x\le\:π
4sin^2(x)+3tan(x)>sec^2(x)	4\sin^{2}(x)+3\tan(x)>\sec^{2}(x)
sin(4x+17)>0	\sin(4x+17^{\circ\:})>0
3sin((pix)/(12)-pi/2)<=-2	3\sin(\frac{πx}{12}-\frac{π}{2})\le\:-2
-sin(x)(2+sin(x))-cos^2(x)>0	-\sin(x)(2+\sin(x))-\cos^{2}(x)>0
sin(pi/6)cos(x)+cos(pi/6)sin(x)<= 1	\sin(\frac{π}{6})\cos(x)+\cos(\frac{π}{6})\sin(x)\le\:1
1/(sqrt(3))<tan(x)	\frac{1}{\sqrt{3}}<\tan(x)
6cos(θ)>= 0	6\cos(θ)\ge\:0
arctan(x^4)>0.0001	\arctan(x^{4})>0.0001
cos(2x)>0,sin(x)>0	\cos(2x)>0,\sin(x)>0
2sin(2x)<= 0	2\sin(2x)\le\:0
cos^3(x)>0	\cos^{3}(x)>0
tan^3(x)<=-sqrt(3)tan(x)	\tan^{3}(x)\le\:-\sqrt{3}\tan(x)
sin^2(pix)>= 1/2	\sin^{2}(πx)\ge\:\frac{1}{2}
4sin(2x)+3cos(x)<= 1	4\sin(2x)+3\cos(x)\le\:1
2sin^2(x)+cos(x)-1>= 0	2\sin^{2}(x)+\cos(x)-1\ge\:0
(2sin(x)-1)/(3cos(x))<= 0	\frac{2\sin(x)-1}{3\cos(x)}\le\:0
sin(2x)-1/2 <0	\sin(2x)-\frac{1}{2}<0
cos^2(x)> 1/4 ,0<= x<= 2pi	\cos^{2}(x)>\frac{1}{4},0\le\:x\le\:2π
sin((x*pi}{(\frac{1+sqrt(5))/2)^2})>0	\sin(\frac{x\cdot\:π}{(\frac{1+\sqrt{5}}{2})^{2}})>0
2sin(x)-sqrt(3)<= 0	2\sin(x)-\sqrt{3}\le\:0
cos(x)<=-(sqrt(2))/2	\cos(x)\le\:-\frac{\sqrt{2}}{2}
(2+sqrt(3)sin(x))<0	(2+\sqrt{3}\sin(x))<0
2cos(x)-1>0	2\cos(x)-1>0
sin(2x)-cos(2x)>0	\sin(2x)-\cos(2x)>0
8>cos(θ),<-9,-4>*<-9	8>\cos(θ),<-9,-4>\cdot\:<-9
cos(2x)+0.5>0	\cos(2x)+0.5>0
tan(x)-(sqrt(3))/3 <= 0	\tan(x)-\frac{\sqrt{3}}{3}\le\:0
arctan(n)-pi/2 <0.0001	\arctan(n)-\frac{π}{2}<0.0001
tan(x)*(2tan(x))/(1-tan^2(x))>1	\tan(x)\cdot\:\frac{2\tan(x)}{1-\tan^{2}(x)}>1

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