What are the solutions to the equation 2x^4+5x^3-12x^2=0 ?

The solutions to the equation 2x^4+5x^3-12x^2=0 are x=0,x= 3/2 ,x=-4

Find the zeros of 2x^4+5x^3-12x^2=0

The zeros of 2x^4+5x^3-12x^2=0 are x=0,x= 3/2 ,x=-4

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2 x^{4} + 5 x^{3} - 12 x^{2} = 0

x = 0, x = \frac{3}{2}, x = - 4

Decimal Notation

x = 0, x = 1.5, x = - 4

Solution steps

2 x^{4} + 5 x^{3} - 12 x^{2} = 0

Factor

2 x^{4} + 5 x^{3} - 12 x^{2} : x^{2} (2 x - 3) (x + 4)

x^{2} (2 x - 3) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x - 3 = 0 or x + 4 = 0

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

x + 4 = 0 : x = - 4

The solutions are

x = 0, x = \frac{3}{2}, x = - 4

x^{3} - 6 x^{2} - 36 x = - 216

c x^{2} + 2 x = x^{3} - c x

2 t^{3} - 3 t^{2} - 12 t - 42 = 0

4 x^{3} - 24 x^{2} + 32 x = 0

x^{3} + 2022 x^{2} = 20222022

What are the solutions to the equation 2x^4+5x^3-12x^2=0 ?
The solutions to the equation 2x^4+5x^3-12x^2=0 are x=0,x= 3/2 ,x=-4
Find the zeros of 2x^4+5x^3-12x^2=0
The zeros of 2x^4+5x^3-12x^2=0 are x=0,x= 3/2 ,x=-4