(9x^2-9y^2)+18xyi=32-24

解答

(9 x^{2} - 9 y^{2}) + 18 x y i = 32 - 24

(x = \frac{2 2}{3}, x = - \frac{2 2}{3}, y = 0 y = 0)

求解步骤

(9 x^{2} - 9 y^{2}) + 18 x y i = 32 - 24

将

32 - 24

改写成标准复数形式:

(32 - 24) + 0 i

(9 x^{2} - 9 y^{2}) + 18 x y i = (32 - 24) + 0 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[9 x^{2} - 9 y^{2} = 32 - 24 18 x y = 0]

[9 x^{2} - 9 y^{2} = 32 - 24 18 x y = 0] : (x = \frac{2 2}{3}, x = - \frac{2 2}{3}, y = 0 y = 0)

(x = \frac{2 2}{3}, x = - \frac{2 2}{3}, y = 0 y = 0)

(2 + 2 i) (x + i y) = (2 + i)^{2}

i (p) = 3500 - 24 p^{2}

so l v e f or E, x = \frac{R}{R + E} i (E)

so l v e f or x, x^{2} - y^{2} i f x = - 3

(m - \frac{1}{2}) (m - 3 - i) = 0