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Popular >

2cos^2(x-1)=0

Solución

2 cos^{2} (x - 1) = 0

Solución

x = \frac{π}{2} + 2 πn + 1, x = \frac{3 π}{2} + 2 πn + 1

+1

Grados

x = 147.29577 \dots^{\circ} + 36 0^{\circ} n, x = 327.29577 \dots^{\circ} + 36 0^{\circ} n

Pasos de solución

2 cos^{2} (x - 1) = 0

Dividir ambos lados entre

2

2 cos^{2} (x - 1) = 0

Dividir ambos lados entre

2

2 cos^{2} (x - 1) = 0

Dividir ambos lados entre

2

\frac{2 cos ^{2} ( x - 1 )}{2} = \frac{0}{2}

Simplificar

cos^{2} (x - 1) = 0

cos^{2} (x - 1) = 0

Aplicar la regla

x^{n} = 0 \Rightarrow x = 0

cos (x - 1) = 0

Soluciones generales para

cos (x - 1) = 0

cos (x)

tabla de valores periódicos con

2 πn

intervalos:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x - 1 = \frac{π}{2} + 2 πn, x - 1 = \frac{3 π}{2} + 2 πn

x - 1 = \frac{π}{2} + 2 πn, x - 1 = \frac{3 π}{2} + 2 πn

Resolver

x - 1 = \frac{π}{2} + 2 πn : x = \frac{π}{2} + 2 πn + 1

x - 1 = \frac{π}{2} + 2 πn

Mover

1

al lado derecho

x - 1 = \frac{π}{2} + 2 πn

Sumar

1

a ambos lados

x - 1 + 1 = \frac{π}{2} + 2 πn + 1

Simplificar

x = \frac{π}{2} + 2 πn + 1

x = \frac{π}{2} + 2 πn + 1

Resolver

x - 1 = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{2} + 2 πn + 1

x - 1 = \frac{3 π}{2} + 2 πn

Mover

1

al lado derecho

x - 1 = \frac{3 π}{2} + 2 πn

Sumar

1

a ambos lados

x - 1 + 1 = \frac{3 π}{2} + 2 πn + 1

Simplificar

x = \frac{3 π}{2} + 2 πn + 1

x = \frac{3 π}{2} + 2 πn + 1

x = \frac{π}{2} + 2 πn + 1, x = \frac{3 π}{2} + 2 πn + 1

Ejemplos populares

1/(cot^2(x))+(sqrt(3))/(cot(x))=0

\frac{1}{cot ^{2} ( x )} + \frac{3}{cot ( x )} = 0

solvefor b,(sin(65)}{14}=\frac{sin(b))/9 resolver para

b, \frac{sin ( 6 5 ^{\circ} )}{14} = \frac{sin ( b )}{9}

4sin(θ)=sin(2θ)

4 sin (θ) = sin (2 θ)

2sin(3x+(3pi)/2)=1

2 sin (3 x + \frac{3 π}{2}) = 1

n=(2tan^3(2θ)-1)^{1/2}

n = (2 tan^{3} (2 θ) - 1)^{\frac{1}{2}}