solvefor b,(sin(65)}{14}=\frac{sin(b))/9

Solução

resolver para

b, \frac{sin ( 6 5 ^{\circ} )}{14} = \frac{sin ( b )}{9}

b = 0.62195 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.62195 \dots + 36 0^{\circ} n

Radianos

b = 0.62195 \dots + 2 πn, b = π - 0.62195 \dots + 2 πn

Passos da solução

\frac{sin ( 6 5 ^{\circ} )}{14} = \frac{sin ( b )}{9}

Trocar lados

\frac{sin ( b )}{9} = \frac{sin ( 6 5 ^{\circ} )}{14}

Multiplicar ambos os lados por

9

\frac{sin ( b )}{9} = \frac{sin ( 6 5 ^{\circ} )}{14}

Multiplicar ambos os lados por

9

\frac{9 sin ( b )}{9} = \frac{9 sin ( 6 5 ^{\circ} )}{14}

Simplificar

sin (b) = \frac{9 sin ( 6 5 ^{\circ} )}{14}

sin (b) = \frac{9 sin ( 6 5 ^{\circ} )}{14}

Aplique as propriedades trigonométricas inversas

sin (b) = \frac{9 sin ( 6 5 ^{\circ} )}{14}

Soluções gerais para

sin (b) = \frac{9 sin ( 6 5 ^{\circ} )}{14}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

b = arcsin (\frac{9 sin ( 6 5 ^{\circ} )}{14}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{9 sin ( 6 5 ^{\circ} )}{14}) + 36 0^{\circ} n

b = arcsin (\frac{9 sin ( 6 5 ^{\circ} )}{14}) + 36 0^{\circ} n, b = 18 0^{\circ} - arcsin (\frac{9 sin ( 6 5 ^{\circ} )}{14}) + 36 0^{\circ} n

Mostrar soluções na forma decimal

b = 0.62195 \dots + 36 0^{\circ} n, b = 18 0^{\circ} - 0.62195 \dots + 36 0^{\circ} n

4 sin (θ) = sin (2 θ)

2 sin (3 x + \frac{3 π}{2}) = 1

n = (2 tan^{3} (2 θ) - 1)^{\frac{1}{2}}

0 = 2 sin (x + 1) + 1

tan (θ) \cdot 10 = 10