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受欢迎的三角函数 >

sin(θ)+cos(θ)=(sqrt(3))/2

解答

sin (θ) + cos (θ) = \frac{3}{2}

解答

θ = 0.65905 \dots + 2 πn - \frac{π}{4}, θ = π - 0.65905 \dots + 2 πn - \frac{π}{4}

+1

度数

θ = - 7.23875 \dots^{\circ} + 36 0^{\circ} n, θ = 97.23875 \dots^{\circ} + 36 0^{\circ} n

求解步骤

sin (θ) + cos (θ) = \frac{3}{2}

使用三角恒等式改写

sin (θ) + cos (θ)

sin (θ) + cos (θ) = 2 sin (θ + \frac{π}{4})

sin (θ) + cos (θ)

改写为

= 2 (\frac{1}{2} sin (θ) + \frac{1}{2} cos (θ))

使用以下普通恒等式:

cos (\frac{π}{4}) = \frac{1}{2}

使用以下普通恒等式:

sin (\frac{π}{4}) = \frac{1}{2}

= 2 (cos (\frac{π}{4}) sin (θ) + sin (\frac{π}{4}) cos (θ))

使用角和恒等式:

sin (s + t) = sin (s) cos (t) + cos (s) sin (t)

= 2 sin (θ + \frac{π}{4})

= 2 sin (θ + \frac{π}{4})

2 sin (θ + \frac{π}{4}) = \frac{3}{2}

两边除以

2

2 sin (θ + \frac{π}{4}) = \frac{3}{2}

两边除以

2

\frac{2 sin ( θ + \frac{π}{4} )}{2} = \frac{\frac{3}{2}}{2}

化简

\frac{2 sin ( θ + \frac{π}{4} )}{2} = \frac{\frac{3}{2}}{2}

化简

\frac{2 sin ( θ + \frac{π}{4} )}{2} : sin (θ + \frac{π}{4})

\frac{2 sin ( θ + \frac{π}{4} )}{2}

约分:

2

= sin (θ + \frac{π}{4})

化简

\frac{\frac{3}{2}}{2} : \frac{6}{4}

\frac{\frac{3}{2}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3}{2 2}

\frac{3}{2 2}

有理化:

\frac{6}{4}

\frac{3}{2 2}

乘以共轭根式

\frac{2}{2}

= \frac{3 2}{2 2 2}

32 = 6

32

使用根式运算法则:

a b = a \cdot b

32 = 3 \cdot 2

= 3 \cdot 2

数字相乘:

3 \cdot 2 = 6

= 6

222 = 4

222

使用指数法则:

a^{b} \cdot a^{c} = a^{b + c}

222 = 2 \cdot 2^{\frac{1}{2}} \cdot 2^{\frac{1}{2}} = 2^{1 + \frac{1}{2} + \frac{1}{2}}

= 2^{1 + \frac{1}{2} + \frac{1}{2}}

同类项相加:

\frac{1}{2} + \frac{1}{2} = 2 \cdot \frac{1}{2}

= 2^{1 + 2 \cdot \frac{1}{2}}

2 \cdot \frac{1}{2} = 1

2 \cdot \frac{1}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

约分:

2

= 1

= 2^{1 + 1}

数字相加:

1 + 1 = 2

= 2^{2}

2^{2} = 4

= 4

= \frac{6}{4}

= \frac{6}{4}

sin (θ + \frac{π}{4}) = \frac{6}{4}

sin (θ + \frac{π}{4}) = \frac{6}{4}

sin (θ + \frac{π}{4}) = \frac{6}{4}

使用反三角函数性质

sin (θ + \frac{π}{4}) = \frac{6}{4}

sin (θ + \frac{π}{4}) = \frac{6}{4}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ + \frac{π}{4} = arcsin (\frac{6}{4}) + 2 πn, θ + \frac{π}{4} = π - arcsin (\frac{6}{4}) + 2 πn

θ + \frac{π}{4} = arcsin (\frac{6}{4}) + 2 πn, θ + \frac{π}{4} = π - arcsin (\frac{6}{4}) + 2 πn

解

θ + \frac{π}{4} = arcsin (\frac{6}{4}) + 2 πn : θ = arcsin (\frac{3}{2 2}) + 2 πn - \frac{π}{4}

θ + \frac{π}{4} = arcsin (\frac{6}{4}) + 2 πn

化简

arcsin (\frac{6}{4}) + 2 πn : arcsin (\frac{3}{2 2}) + 2 πn

arcsin (\frac{6}{4}) + 2 πn

\frac{6}{4} = \frac{3}{2 2}

\frac{6}{4}

分解

6 : 23

因式分解

6 = 2 \cdot 3

= 2 \cdot 3

使用根式运算法则:

n ab = n a n b

= 23

分解

4 : 2^{2}

因式分解

4 = 2^{2}

= \frac{2 3}{2 ^{2}}

消掉

\frac{2 3}{2 ^{2}} : \frac{3}{2 ^{\frac{3}{2}}}

\frac{2 3}{2 ^{2}}

使用根式运算法则:

n a = a^{\frac{1}{n}}

2 = 2^{\frac{1}{2}}

= \frac{2 ^{\frac{1}{2}} 3}{2 ^{2}}

使用指数法则:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{2 ^{\frac{1}{2}}}{2 ^{2}} = \frac{1}{2 ^{2 - \frac{1}{2}}}

= \frac{3}{2 ^{2 - \frac{1}{2}}}

数字相减:

2 - \frac{1}{2} = \frac{3}{2}

= \frac{3}{2 ^{\frac{3}{2}}}

= \frac{3}{2 ^{\frac{3}{2}}}

2^{\frac{3}{2}} = 22

2^{\frac{3}{2}}

2^{\frac{3}{2}} = 2^{1 + \frac{1}{2}}

= 2^{1 + \frac{1}{2}}

使用指数法则:

x^{a + b} = x^{a} x^{b}

= 2^{1} \cdot 2^{\frac{1}{2}}

整理后得

= 22

= \frac{3}{2 2}

= arcsin (\frac{3}{2 2}) + 2 πn

θ + \frac{π}{4} = arcsin (\frac{3}{2 2}) + 2 πn

将

\frac{π}{4}

到右边

θ + \frac{π}{4} = arcsin (\frac{3}{2 2}) + 2 πn

两边减去

\frac{π}{4}

θ + \frac{π}{4} - \frac{π}{4} = arcsin (\frac{3}{2 2}) + 2 πn - \frac{π}{4}

化简

θ = arcsin (\frac{3}{2 2}) + 2 πn - \frac{π}{4}

θ = arcsin (\frac{3}{2 2}) + 2 πn - \frac{π}{4}

解

θ + \frac{π}{4} = π - arcsin (\frac{6}{4}) + 2 πn : θ = π - arcsin (\frac{3}{2 2}) + 2 πn - \frac{π}{4}

θ + \frac{π}{4} = π - arcsin (\frac{6}{4}) + 2 πn

化简

π - arcsin (\frac{6}{4}) + 2 πn : π - arcsin (\frac{3}{2 2}) + 2 πn

π - arcsin (\frac{6}{4}) + 2 πn

\frac{6}{4} = \frac{3}{2 2}

\frac{6}{4}

分解

6 : 23

因式分解

6 = 2 \cdot 3

= 2 \cdot 3

使用根式运算法则:

n ab = n a n b

= 23

分解

4 : 2^{2}

因式分解

4 = 2^{2}

= \frac{2 3}{2 ^{2}}

消掉

\frac{2 3}{2 ^{2}} : \frac{3}{2 ^{\frac{3}{2}}}

\frac{2 3}{2 ^{2}}

使用根式运算法则:

n a = a^{\frac{1}{n}}

2 = 2^{\frac{1}{2}}

= \frac{2 ^{\frac{1}{2}} 3}{2 ^{2}}

使用指数法则:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{2 ^{\frac{1}{2}}}{2 ^{2}} = \frac{1}{2 ^{2 - \frac{1}{2}}}

= \frac{3}{2 ^{2 - \frac{1}{2}}}

数字相减:

2 - \frac{1}{2} = \frac{3}{2}

= \frac{3}{2 ^{\frac{3}{2}}}

= \frac{3}{2 ^{\frac{3}{2}}}

2^{\frac{3}{2}} = 22

2^{\frac{3}{2}}

2^{\frac{3}{2}} = 2^{1 + \frac{1}{2}}

= 2^{1 + \frac{1}{2}}

使用指数法则:

x^{a + b} = x^{a} x^{b}

= 2^{1} \cdot 2^{\frac{1}{2}}

整理后得

= 22

= \frac{3}{2 2}

= π - arcsin (\frac{3}{2 2}) + 2 πn

θ + \frac{π}{4} = π - arcsin (\frac{3}{2 2}) + 2 πn

将

\frac{π}{4}

到右边

θ + \frac{π}{4} = π - arcsin (\frac{3}{2 2}) + 2 πn

两边减去

\frac{π}{4}

θ + \frac{π}{4} - \frac{π}{4} = π - arcsin (\frac{3}{2 2}) + 2 πn - \frac{π}{4}

化简

θ = π - arcsin (\frac{3}{2 2}) + 2 πn - \frac{π}{4}

θ = π - arcsin (\frac{3}{2 2}) + 2 πn - \frac{π}{4}

θ = arcsin (\frac{3}{2 2}) + 2 πn - \frac{π}{4}, θ = π - arcsin (\frac{3}{2 2}) + 2 πn - \frac{π}{4}

以小数形式表示解

θ = 0.65905 \dots + 2 πn - \frac{π}{4}, θ = π - 0.65905 \dots + 2 πn - \frac{π}{4}

作图

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