convert 5 d to y

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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Steps Examples

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x+2y=2x−5, x−y=3

Solution

x=1, y=−2

Show Steps

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Solve by:

Usando el método de eliminación

Usando el método de sustitución

Resolver por regla de Cramer

Resolver por eliminación de Gauss

One step at a time

[

x+2y=2x−5

x−y=3

]

Ordenar las variables de la ecuación para su eliminación

[

−x+2y=−5

x−y=3

]

Sumar las ecuaciones

x−y=3

−x+2y=−5

y=−2

[

−x+2y=−5

y=−2

]

Para −x+2y=−5 sustituir y=−2

Resolver −x+2(−2)=−5 para x: x=1

Las soluciones para el sistema de ecuaciones son:

x=1, y=−2

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Resolver por lo siguiente: Usando el método de sustitución

Resolver por lo siguiente: Resolver por regla de Cramer

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

convert 5 d to y

Solution

Solution steps

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