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inversa (x(x-1)^2)/(x^2-1)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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inverse x²+x+1x

Solution

−1+x+√x²−2x−32 , −1+x−√x²−2x−32

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ddx (ln(3x²))

Aplicar la regla de la cadena: 13x² ddx (3x²)

=13x² ddx (3x²)

ddx (3x²)=6x

=13x² · 6x

Simplificar 13x² · 6x: 2x

=2x

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domain x²+x+1x

range x²+x+1x

intercepts x²+x+1x

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inversa (x(x-1)^2)/(x^2-1)

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