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eigenvalores (
1
2
1
6
−1
0
−1
−2
−1
)
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Solution
λ=0,λ=3,λ=−4
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(
1
2
1
6
−1
0
−1
−2
−1
)
Valores propios de una matriz
Sea Auna matriz cuadrada, ηun vector y λun escalar que satisface Aη=λλ, entonces λes llamado el valor propio asociado con el vector propio λde A
Los valores propios de Ason las raices de la ecuación caracteristica det(A−λI)=0