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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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serie de fourier 1−x², [−1, 1]

Solution

23 +∑_n=1^∞−4(−1)ⁿcos(πnx)π²n²

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Solution steps

One step at a time

(

1	2	1
6	−1	0
−1	−2	−1

)

Vectores propios de una matriz

Sea A una matriz cuadrada, η un vector y λ un escalar que satisface Aη=λη,
entonces η es un vector propio de A y λ es el valor propio asociado a el

Para encontrar los vectores propiosη, resolver (A−λ I)η=0 para cada valor propio λ

Encontrar los valores propios de (

1	2	1
6	−1	0
−1	−2	−1

): λ=0, λ=3, λ=−4

Vectores propios de λ=0: (

−1

−6

)

Vectores propios de λ=3: (

−2

−3

)

Vectores propios de λ=−4: (

−1

)

Los vectores propios de (

1	2	1
6	−1	0
−1	−2	−1

)

−1

−6

), (

−2

−3

), (

−1

)

Coin Problems Examples

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

24	0	1
8	−13	10
7	8	−5

Coin Problems Calculator

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