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∫x3−5(x−3)2dx
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Solution
x22+6x+27ln|x−3|−22x−3+C
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∫x3−5(x−3)2dx
División larga x3−5(x−3)2:x+6+27x−59x2−6x+9
=∫x+6+27x−59x2−6x+9dx
Aplicar la regla de la suma: ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx