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vertices y=9-x^2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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desarrollar (x+4)⁴

Solution

x⁴+16x³+96x²+256x+256

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L⁻¹{5x³+1x²−4 }

Tomar la fracción parcial de 5x³+1x²−4 : 5x+394(x+2) +414(x−2)

=L⁻¹{5x+394(x+2) +414(x−2) }

Usar la propiedad de linealidad de la transformada inversa de Laplace:
Para las funciones f(s), g(s) y constantes a, b: L⁻¹{a·f(s)+b·g(s)}=a·L⁻¹{f(s)}+b·L⁻¹{g(s)}

=5L⁻¹{x}+L⁻¹{394(x+2) }+L⁻¹{414(x−2) }

L⁻¹{x}: δ′ (t)

L⁻¹{394(x+2) }: 394 e^−2t

L⁻¹{414(x−2) }: 414 e^2t

=5δ′ (t)+394 e^−2t+414 e^2t

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

vertices y=9-x^2

Solution

Solution steps

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