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Radicals Divide Calculator

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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eigenvectors (

2	−1	0
5	2	4
0	1	2

)

Solution

(

−4

), (

−1

i

), (

−1

−i

)

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Solution steps

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(

2	−1	0
5	2	4
0	1	2

)

Matrix eigenvectors

Let A be a square matrix, η a vector and λ a scalar that satisfy Aη=λη,
then η is an eigenvector of A and λ is the eigenvalue associated with it

To find the eigenvectors η, solve (A−λ I)η=0 for each eigenvalue λ

Find the eigenvalues for (

2	−1	0
5	2	4
0	1	2

): λ=2, λ=2+i, λ=2−i

Eigenvectors for λ=2: (

−4

)

Eigenvectors for λ=2+i: (

−1

i

)

Eigenvectors for λ=2−i: (

−1

−i

)

The eigenvectors for (

2	−1	0
5	2	4
0	1	2

)

−4

), (

−1

i

), (

−1

−i

)

Radicals Divide Examples

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Hola, haz una pregunta sobre eigenvectors (

2	−1	0
5	2	4
0	1	2

) o elige a continuación

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

Radicals Divide Calculator

Solution

Solution steps

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