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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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One card is selected at random from a deck of cards. Determine the probability that the card selected is a 9.

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

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log_□

π

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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Generated by AI

nth term a₁=−20, a₅=−1620, r=3

Solution

a_n=−20· 3ⁿ⁻¹

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Solution steps

One step at a time

Seleccionar valores de z-valores: −2, −1, 0, 1, 2

Calcula los valores de la función −5z+13:

−5z+13, z=−2: 23

−5z+13, z=−1: 18

−5z+13, z=0: 13

−5z+13, z=1: 8

−5z+13, z=2: 3

Resume en una tabla de valores:

`z`	−5`z`+13
−2	23
−1	18
0	13
1	8
2	3

Puntos de valor:

(−2, 23), (−1, 18), (0, 13), (1, 8), (2, 3)

Solve instead

sequence type a₁=−20, a₅=−1620, r=3

first term a₁=−20, a₅=−1620, r=3

next term a₁=−20, a₅=−1620, r=3

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