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domain of and range f(x)=ln (x-5)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
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domain and range f(x)=ln(x−5)

Solution

Domain: x>5

Range: −∞ <f(x)<∞

Interval Notation

Domain: (5, ∞ )

Range: (−∞ , ∞ )

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Domain of ln(x−5) : x>5

Range of ln(x−5): −∞ <f(x)<∞

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inverse ln(x−5)

intercepts ln(x−5)

parity ln(x−5)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

domain of and range f(x)=ln (x-5)

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